Php 在<;中显示MySQL数据;选择>;弱点
我只是想显示一个htmlPhp 在<;中显示MySQL数据;选择>;弱点,php,mysql,Php,Mysql,我只是想显示一个html下拉列表,显示MySQL数据库行中的选项。据我所知,这应该是可行的。但是,它不会在下拉列表中显示任何内容。活动表的活动ID和名称列中肯定有数据。不知道为什么它没有显示任何内容。请帮忙 应显示name campaign_create.php 您需要回显关闭选择标记。只要在你的循环之后加上这一行,你就没事了 echo '</select>'; 首先,您的HTML标记永远不会用关闭 其次,$con变量在changemactive功能范围内不可用。添加global$
下拉列表,显示MySQL数据库行中的选项。据我所知,这应该是可行的。但是,它不会在下拉列表中显示任何内容。活动
表的活动ID
和名称
列中肯定有数据。不知道为什么它没有显示任何内容。请帮忙
应显示name
campaign_create.php
您需要回显关闭选择标记。只要在你的循环之后加上这一行,你就没事了
echo '</select>';
首先,您的
HTML标记永远不会用
关闭
其次,$con
变量在changemactive
功能范围内不可用。添加global$con代码>到函数的开头以修复它
此外,我更喜欢用这种东西跳进跳出PHP块。考虑这个代码:
<?php
//include db connect
include ("db_con.php");
//campaign change form function
function changeCampaign() {
global $con; // we need the connection data in here.
//set variables
$query = mysqli_query($con,"SELECT * FROM campaigns");
?>
<table border="1">
<form action="functions/campaign_change.php" name="campaignChange" method="post">
<tr>
<td><select name="campaignList">';
<?php
//loop that is NOT displaying the name
while ($row = mysqli_fetch_array($query)) {
echo "<option value='" . $row['campaignid'] . "'>" . $row['name'] . "</option>";
}
?>
</select></td>
</tr>
<tr>
<td><input type="submit" value="Load" /></td>
</tr>
</form>
</table>';
<?php
}
?>
';
';
在这种情况下,输出的HTML代码就像是echo
ed一样,但它要好得多。您的
标记没有关闭。没问题,我几周前自己做的,实际上关闭
没有帮助。。。我用新代码更新了原来的帖子。我真傻,竟然忘了结尾的标签。但是,在添加它时,它仍然没有显示名称。你能告诉我当循环运行时,?此外,是否存在任何错误?如果“for”循环指的是“while”循环,则它似乎没有运行。另外,我没有意识到任何错误。好的,我尝试创建一个变量$num=mysqli\u num\u rows($query)
,并回显变量$num
,它只是空白。我做错了吗?我添加了错误报告(E\u ALL)代码>在开头。它一无所获。我还添加了一些代码,用于创建访问同一数据库的同一表的活动。这个很好用。我在这里完全糊涂了。
<?php
//include db connect
include ("db_con.php");
//start session
session_start();
//set variable names
$username = $_SESSION['username'];
$campaignname = addslashes($_POST['name']);
//validate campaign name length
if ((strlen($campaignname) < 6) || (strlen($campaignname) > 55)) {
echo 'Campaign name must be between 6 and 55 characters - Please go back and try again.';
exit;
}
//create new campaign
$query = mysqli_query($con, "INSERT INTO campaigns (creator, name) VALUES ('".$username."', '".$campaignname."')");
if ($query) {
echo 'Campaign created successfully!';
header( "refresh:2;url=../index.php" );
} else {
echo 'There was an unknown error in creating the campaign - Please go back and try again.';
}
?>
echo '</select>';
while ($row = mysqli_fetch_array($con, $query)) {
<?php
//include db connect
include ("db_con.php");
//campaign change form function
function changeCampaign() {
global $con; // we need the connection data in here.
//set variables
$query = mysqli_query($con,"SELECT * FROM campaigns");
?>
<table border="1">
<form action="functions/campaign_change.php" name="campaignChange" method="post">
<tr>
<td><select name="campaignList">';
<?php
//loop that is NOT displaying the name
while ($row = mysqli_fetch_array($query)) {
echo "<option value='" . $row['campaignid'] . "'>" . $row['name'] . "</option>";
}
?>
</select></td>
</tr>
<tr>
<td><input type="submit" value="Load" /></td>
</tr>
</form>
</table>';
<?php
}
?>