Php 在csv\u from\u result方法中,将我们的codeigniter查询对象中的mysql时间戳转换为日期
我有以下代码:Php 在csv\u from\u result方法中,将我们的codeigniter查询对象中的mysql时间戳转换为日期,php,mysql,codeigniter,date,time,Php,Mysql,Codeigniter,Date,Time,我有以下代码: $query = $this->EE->db->select('*')->where('form_name', 'Newsletter')->get('freeform_entries'); $filename = "newsletter.csv"; $path = "some/path"; $delimiter = ","; $newline = "\r\n"; $cs
$query = $this->EE->db->select('*')->where('form_name', 'Newsletter')->get('freeform_entries');
$filename = "newsletter.csv";
$path = "some/path";
$delimiter = ",";
$newline = "\r\n";
$csv_data = $this->EE->dbutil->csv_from_result($query, $delimiter, $newline);
但其中一个字段是时间戳,我需要将它转换为日期时间,这样当输出到csv时,它看起来就是这样。所以我需要20-10-13 09:28而不是1357752502
有什么想法吗?FROM_UNIXTIME将unix_timestamp参数的表示形式作为'YYYY-MM-DD HH:MM:SS'中的值返回:
$query = $this->EE->db->select('FROM_UNIXTIME(timestamp_field) AS "value"', ... )->where('form_name', 'Newsletter')->get('freeform_entries');
$filename = "newsletter.csv";
$path = "some/path";
$delimiter = ",";
$newline = "\r\n";
$csv_data = $this->EE->dbutil->csv_from_result($query, $delimiter, $newline);
更多信息:这里只需一个简短的问题:'从作为“值”的UNIXTIME(timestamp_字段),…)我该怎么说:以及所有其他字段,例如a*?哦,没关系,忽略它,我有一个拼写错误,但做得对。再次感谢!!