Php 基于键的值合并数组

我有从foreach循环生成的数组，其中包含来自DB的记录，如果email或iduser相同，我希望合并这些记录。看起来像这样

Array
(
    [iduser] => 1
    [email] => email1@example.com
    [firstname] => Jan
    [lastname] => Novotny
    [phone] =>
    [created] => 2011-10-28 16:53:33
    [last_action] => 2016-08-17 12:53:08
    [idclient] => 1
    [vat_type] => quarterly
    [eet] => 0
    [accounting_type] => accountancy
)

Array
(
    [iduser] => 1
    [email] => email1@example.com
    [firstname] => Jan
    [lastname] => Novotny
    [phone] =>
    [created] => 2013-11-12 18:09:11
    [last_action] => 2017-01-12 10:30:38
    [idclient] => 3
    [vat_type] => monthly
    [eet] => 1
    [accounting_type] => tax_registration
)
Array
(
    [iduser] => 7
    [email] => email2@example.com
    [firstname] => Honza
    [lastname] => Novak
    [phone] =>
    [created] => 2015-10-28 16:53:33
    [last_action] => 2010-01-27 02:18:09
    [idclient] => 336
    [vat_type] => quarterly
    [eet] => 0
    [accounting_type] => tax_registration
)

期望的输出是这样的

Array
(
     [iduser] => 1
     [email] => email1@example.com
     [firstname] => Jan
     [lastname] => Novotny
     [phone] =>
     [created] => array(
                       [0]=> 2011-10-28 16:53:33
                       [1]=> 2013-11-12 18:09:11
     [last_action] => array(
                           [0]=> 2016-08-17 12:53:08
                           [1]=> 2017-01-12 10:30:38
     [idclient] => array(
                        [0]=> 1
                        [1]=> 3
     [vat_type] => array(
                        [0]=> quarterly
                        [1]=> monthly
     [eet] => array(
                   [0]=> 0
                   [1]=> 1
     [accounting_type] => array(
                               [0]=> accountancy
                               [1]=> tax_registration
)
Array
(
     [iduser] => 7
     [email] => email2@example.com
     [firstname] => Honza
     [lastname] => Novak
     [phone] =>
     [created] => 2015-10-28 16:53:33
     [last_action] => 2010-01-27 02:18:09
     [idclient] => 336
     [vat_type] => quarterly
     [eet] => 0
     [accounting_type] => tax_registration
)
..... etc

---

我试图通过array\u merge（）和array\u replace\u recursive（）来实现这一点，但没有找到有效的解决方案，也没有在有关stackoverflow的问题中找到答案。我将感谢您的帮助：）

您有没有看到@DanielRahman您的概念不是最佳的。您应该只选择一个“唯一标识符”进行合并。通过选择两个标识符，代码必须“决定”应该保留哪个

iduser

和哪个

email

，这并不好。由于

电子邮件

对于每个用户都是唯一的，我强烈建议您重新考虑您的概念/问题，并比较

电子邮件

上的子数组。然后快速搜索你的新问题，因为你会找到一页又一页的答案。你的问题几乎每天都被重复。