Php 使用带页段塞的数组
我使用以下代码根据类别id显示图像:Php 使用带页段塞的数组,php,wordpress,Php,Wordpress,我使用以下代码根据类别id显示图像: <?php if (is_category( 'web-design' )){ ?> <img src="<?php bloginfo('template_directory'); ?>/images/slider_webdesign.png" title="خدمات تصميم وتطوير المواقع" height="200px" width="960px" /> <?php }else if (
<?php
if (is_category( 'web-design' )){
?>
<img src="<?php bloginfo('template_directory'); ?>/images/slider_webdesign.png" title="خدمات تصميم وتطوير المواقع" height="200px" width="960px" />
<?php
}else if (is_category( 'printing' )){
?>
<img src="<?php bloginfo('template_directory'); ?>/images/slider_printing.png" title="تصميم مطبوعات" height="200px" width="960px" />
<?php
}else if (is_category( 'online-marketing' )){
?>
/图像/滑块网页设计.png“title=”200px“width=”960px“>
/图像/滑块打印.png“title=”200px“width=”960px“/>
我想制作一个只包含一个条件的数组,以显示带有类别slug的图像,这可能吗?
<?php
$categories = array(
'web-design' => array(
'image' => 'slider_webdesign.png',
'title' => 'Title of image',
'height' => '200',
'width' => '960'
),
'template_directory' => array(
'image' => 'slider_printing.png',
'title' => 'Title of image',
'height' => '200',
'width' => '960'
)
);
$category = false;
/* following code might need rewriting since I'm not sure if this is the */
/* correct way of getting current category slug */
if (is_category()) {
$slug = get_category(get_query_var('cat'))->slug;
if (isset($categories[$slug])) {
$category = $categories[$slug];
}
}
?>
<?php if ($category): ?>
<img src="<?php bloginfo('template_directory'); ?>/images/<?=$category['image']?>" title="<?=$category['title']?>" height="<?=$category['height']?>" width="<?=$category['width']?>" />
<?php endif ?>