Php Symfony4使用ajax调用请求数据为空
我是Symfony4的新手,所以这可能是一个noob问题。但我想不起来 把它弄出来 我正在尝试使用ajax调用注册用户:Php Symfony4使用ajax调用请求数据为空,php,laravel,symfony,Php,Laravel,Symfony,我是Symfony4的新手,所以这可能是一个noob问题。但我想不起来 把它弄出来 我正在尝试使用ajax调用注册用户: this.form.post('/register').then((response) => { console.log(response); }); 然后在symfony中,我的控制器方法如下所示: /** * @Route("/register", name="register", methods={"POST"}) * @param Request
this.form.post('/register').then((response) => {
console.log(response);
});
然后在symfony中,我的控制器方法如下所示:
/**
* @Route("/register", name="register", methods={"POST"})
* @param Request $request
* @param UserPasswordEncoderInterface $passwordEncoder
* @return JsonResponse
*/
public function register(Request $request, UserPasswordEncoderInterface $passwordEncoder)
{
$user = new User();
// encode the plain password
$user->setPassword(
$passwordEncoder->encodePassword(
$user,
$request->request->get('password')
)
);
$user->setEmail($request->request->get('email'));
$user->setName($request->request->get('name'));
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($user);
$entityManager->flush();
return $this->json(['success' => 'User created']);
}
问题是数据总是空的。数据发送正确。当我在控制器中添加响应时,我看到:
我的标题等如下所示:
/**
* @Route("/register", name="register", methods={"POST"})
* @param Request $request
* @param UserPasswordEncoderInterface $passwordEncoder
* @return JsonResponse
*/
public function register(Request $request, UserPasswordEncoderInterface $passwordEncoder)
{
$user = new User();
// encode the plain password
$user->setPassword(
$passwordEncoder->encodePassword(
$user,
$request->request->get('password')
)
);
$user->setEmail($request->request->get('email'));
$user->setName($request->request->get('name'));
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($user);
$entityManager->flush();
return $this->json(['success' => 'User created']);
}
请求有效负载如下所示:
/**
* @Route("/register", name="register", methods={"POST"})
* @param Request $request
* @param UserPasswordEncoderInterface $passwordEncoder
* @return JsonResponse
*/
public function register(Request $request, UserPasswordEncoderInterface $passwordEncoder)
{
$user = new User();
// encode the plain password
$user->setPassword(
$passwordEncoder->encodePassword(
$user,
$request->request->get('password')
)
);
$user->setEmail($request->request->get('email'));
$user->setName($request->request->get('name'));
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($user);
$entityManager->flush();
return $this->json(['success' => 'User created']);
}
当我和邮递员一起尝试时,我得到了同样的结果。我可能做错了什么?您需要在后端创建一个表单类型来验证新注册的用户,请选中此项。不要忘了更新控制器。在您的小树枝中,您必须定义
let registerPath=“{app.request.getSchemeAndHttpHost()~path('register')}”;
在js中,您可以像这样使用ajax帖子:
this.form.post(registerPath).then((响应)=>{
控制台日志(响应);
});代码>
希望这能有所帮助:)谢谢,但这不是问题所在。这条路是正确的。