用于密码验证的php

我把下面的部分代码贴到了另一个问题上，找到了解决方案。我可以从我的android设备注册、登录和注销，这很好。然而，现在我得到了一些奇怪的东西。我添加了一个额外的功能，以便验证$user_pass和$confirm password变量是否相等（比较字符串）。然而，我总是从这里收到一条json消息“密码不匹配”

if($userPass!==$confirmPass){


        $don = array('result' =>"fail","message"=>"Passwords don't match");

 }

整个代码如下所示

 <?php
  session_start();
  require "init.php";
  header('Content-type: application/json');

  $email = $_POST['email'];
  $user_name = $_POST['user_name'];

  $user_pass = $_POST['user_pass'];
  $passwordEncrypted = sha1($user_pass);  

  $confirmPass = $_POST['confirm_pass'];
  $confPasswordEncrypted = sha1($confirmPass);  

  $msg = "Congratulations. You are now registered to the most amazing app ever!";            

        if(!filter_var($email, FILTER_VALIDATE_EMAIL)){


            $don = array('result' =>"fail","message"=>"Please enter a valid email");

        }




        if($email && $user_name && $user_pass && $confirmPass && filter_var($email, FILTER_VALIDATE_EMAIL)){


        $sql_query = "select * from user_info WHERE email ='".mysqli_real_escape_string($con, $email)."' or user_name 
        ='".mysqli_real_escape_string($con, $user_name)."'";

        $result = mysqli_query($con, $sql_query);   

        $results = mysqli_num_rows($result);

        if ($results){
            $don = array('result' =>"fail","message"=>"Email or username exists.");
        }else{

            $sql_query = "insert into user_info values('$email','$user_name','$passwordEncrypted','$confPasswordEncrypted');";

            if(mysqli_query($con,$sql_query)){

                $don = array('result' =>"success","message"=>"Successfully registered!Well done");
                //mail($email,"Well done",$msg);
                $_SESSION['email']=$row['email'];
            }
        }
    } if(!$email){


        $don = array('result' =>"fail","message"=>"Please enter your email");                  


    }else if(!$user_name){


        $don = array('result' =>"fail","message"=>"Please enter your username");


    }else if(!$user_pass){


        $don = array('result' =>"fail","message"=>"Please enter a password");

     //The last if statement causes the problem.
    }else if($userPass!==$confirmPass){


        $don = array('result' =>"fail","message"=>"Passwords don't match");

    }


      echo json_encode($don);

?>

---

使用链接中描述的strcmp方法
尝试使用

if(!strcmp($userPass,$confirmPass))

而不是

if($userPass!==$confirmPass)

修好了。我有一个额外的父母

if($userPass!==$confirmPass))

所以我把它改成了

if($userPass!==$confirmPass)

：）
使用
if（$userPass！=$confirmPass）{
而不是
if（$userPass！==$confirmPass）{
并检查它是否工作。仍然会遇到相同的问题。也许它们真的不同？您是否尝试了
var\u dump（$userPass，$confirmPass）
？我没有，因为我没有使用html表单。php文件仅为android设备指定。使用strcmp（..）函数，我现在可以注册，即使两个密码不同。请在提问之前清理您的代码