避免mysql和php的重复结果
我正在创建一个带有回复功能的评论系统，我发现遇到了一个问题 评论表 id post_id comment replyTo 0 17 Blah 2 1 17 hello 2 2 17 goodbye 3 17 great 1 4 17 bad避免mysql和php的重复结果,php,mysql,duplicates,distinct,Php,Mysql,Duplicates,Distinct,我正在创建一个带有回复功能的评论系统，我发现遇到了一个问题 评论表 id post_id comment replyTo 0 17 Blah 2 1 17 hello 2 2 17 goodbye 3 17
$comments = mysql_query("SELECT * FROM comment WHERE post_id='$post_id' ORDER BY id DESC");
while($comment = mysql_fetch_assoc($comments))
{
$id = $comment['id'];
$comment = $comment['comment'];
$reply = $comment['replyTo'];
echo $comment;
echo "<br />";
$replyQuery = mysql_query("SELECT * FROM comment WHERE replyTo='$id' ORDER BY id DESC");
while($comment = mysql_fetch_assoc($comments))
{
$id = $comment['id'];
$comment = $comment['comment'];
$reply = $comment['replyTo'];
echo $comment;
echo "<br />";
}
}
$comments = mysql_query("SELECT * FROM comment WHERE post_id='$post_id' ORDER BY id DESC");
while($comment = mysql_fetch_assoc($comments))
{
$id = $comment['id'];
$comment = $comment['comment'];
$reply = $comment['replyTo'];
echo $comment;
echo "<br />";
$replyQuery = mysql_query("SELECT * FROM comment WHERE replyTo='$id' ORDER BY id DESC");
while($comment = mysql_fetch_assoc($comments))
{
$id = $comment['id'];
$comment = $comment['comment'];
$reply = $comment['replyTo'];
echo $comment;
echo "<br />";
}
}
$comments=mysql\u query（“从注释中选择*，其中post\u id='$post\u id'按id顺序描述”）；
while（$comment=mysql\u fetch\u assoc（$comments））
{
$id=$comment['id']；
$comment=$comment['comment']；
$reply=$comment['replyTo']；
回声$评论；
回声“
”；
$replyQuery=mysql_query（“从注释中选择*，其中replyTo='$id'按id DESC排序”）；
while（$comment=mysql\u fetch\u assoc（$comments））
{
$id=$comment['id']；
$comment=$comment['comment']；
$reply=$comment['replyTo']；
回声$评论；
回声“
”；
}
}
谢谢第一行应该是：
$comments = mysql_query("SELECT * FROM comment WHERE post_id='$post_id' AND replyTo IS NULL ORDER BY id DESC");
因此，只包含顶级注释。尝试此查询，它将在单个查询中包含所有结果 选择GROUP_CONCAT（id）作为id，GROUP_CONCAT（post_id）作为post_id，GROUP_CONCAT（comment）作为comment，GROUP_CONCAT（replyTo）作为replyTo 从post_id=17的注释按回复分组到按id描述排序 结果看起来像
id post_id comment replyTo
3 17 great 1
2,4 17,17 goodbye,bad 0,0
0,1 17,17 Blah,hello 2,2
请尝试
<?php
$comments = mysql_query("SELECT GROUP_CONCAT(id) AS id,GROUP_CONCAT(post_id) AS post_id,GROUP_CONCAT(comment) AS comment,GROUP_CONCAT(date) AS date,GROUP_CONCAT(submittedBy) AS submittedBy,GROUP_CONCAT(replyTo) AS replyTo FROM comment WHERE post_id='$post_id' GROUP BY replyTo ORDER BY id DESC");
while($comment = mysql_fetch_assoc($comments))
{
$cid = $comment['id'];
$comment_submit = $comment['submittedBy'];
$submitted_comment = $comment['comment'];
$comment_date = $comment['date'];
$replyTo = $comment['replyTo'];
echo'<div id="c'.$id.'" class="comment_container">';
echo'<div class="comment_header">';
echo'<a href="#" class="report">Flag</a>';
echo'<a href="#" class="reply">Reply</a>';
echo'<span>';
echo $comment_submit.' - '.$comment_date.'</span>';
echo'</div>';
echo'<p>';
echo $submitted_comment;
echo'</p>';
echo'
<form method="post" class="replyForm">
<textarea name="post_data_comment" class="replyTextArea" placeholder="@'.$comment_submit.'"></textarea>
<input type="hidden" name="post_id" value="'.$post_id.'" />
<input type="hidden" name="replyTo" value="'.$cid.'" />
<div class="row_three">
<span class="char_left_reply">Characters left: <span>500</span></span>
<input type="button" value="Reply" name="share_reply" class="reply_comment" />
</div>
</form>
';
echo'</div>';
$reply = mysql_query("SELECT * FROM comment WHERE replyTo='$cid' ORDER BY id DESC");
while($replies = mysql_fetch_assoc($reply))
{
$id = $replies['id'];
$comment_submit = $replies['submittedBy'];
$submitted_comment = $replies['comment'];
$comment_date = $replies['date'];
$replyTo = $replies['replyTo'];
echo'<div id="c'.$id.'" class="comment_container" style="width:90%; float:right" >';
echo'<div class="comment_header">';
echo'<a href="#" class="report">Flag</a>';
echo'<a href="#" class="reply">Reply</a>';
echo'<span>';
echo $comment_submit.' - '.$comment_date.'</span>';
echo'</div>';
echo'<p>';
echo $submitted_comment;
echo'</p>';
echo'
<form method="post" class="replyForm">
<textarea name="post_data_comment" class="replyTextArea" placeholder="@'.$comment_submit.'"></textarea>
<input type="hidden" name="post_id" value="'.$post_id.'" />
<input type="hidden" name="replyTo" value="'.$cid.'" />
<div class="row_three">
<span class="char_left_reply">Characters left: <span>500</span></span>
<input type="button" value="Reply" name="share_reply" class="reply_comment" />
</div>
</form>
';
echo'</div>';
}
$comments = mysql_query("SELECT distinct(comment),id,replyTo FROM comment WHERE post_id='$post_id' ORDER BY id DESC");
while($comment = mysql_fetch_assoc($comments))
{
$id = $comment['id'];
$comment = $comment['comment'];
$reply = $comment['replyTo'];
echo $comment;
echo "<br />";
$replyQuery = mysql_query("SELECT * FROM comment WHERE replyTo='$id' and comment <> '$comment' ORDER BY id DESC");
while($comment = mysql_fetch_assoc($comments))
{
$id = $comment['id'];
$comment = $comment['comment'];
$reply = $comment['replyTo'];
echo $comment;
echo "<br />";
}
}
$comments=mysql\u query（“选择distinct（comment），id，replyTo FROM comment，其中post\u id='$post\u id'按id DESC排序”）；
while（$comment=mysql\u fetch\u assoc（$comments））
{
$id=$comment['id']；
$comment=$comment['comment']；
$reply=$comment['replyTo']；
回声$评论；
回声“
”；
$replyQuery=mysql_query（“从注释中选择*，其中replyTo='$id'和注释'$comment'按id顺序描述”）；
while（$comment=mysql\u fetch\u assoc（$comments））
{
$id=$comment['id']；
$comment=$comment['comment']；
$reply=$comment['replyTo']；
回声$评论；
回声“
”；
}
}
replyTo的默认值是多少？例如，其中id为2。它是空的吗？这个领域的类型是什么？为什么不发布完整的表结构？2和4都是空的，所以这些帖子不会回复任何人。顺便说一句，mysql_*函数已经过时，不应该再使用了。请考虑使用PDO或MyQuiL**，谢谢您的回复。我尝试过类似的方法，例如replyTo=''，但它不会显示所有结果。您需要确保只对顶级注释执行该条件。你也有命名冲突，我一开始没有注意到。在外循环中创建的变量在内循环中被覆盖。请确保内部循环没有修改变量$reply。这不是很有帮助。你能把修改过的代码贴出来吗？还有，你是如何运行它的？它是一个函数还是另一个函数的一部分，等等？谢谢！我是否也将同样的查询应用于内部循环？谢谢您的回复。有了这个，我没有得到我想要的结果。请再次检查，我编辑了它。我希望它会返回我想要的结果