Php 我希望$name是mysql中的所有行,在
这是代码示例,请在此处添加,以解析$name是唯一的最后一个示例:((( 我需要所有这些链接:Php 我希望$name是mysql中的所有行,在,php,mysql,Php,Mysql,这是代码示例,请在此处添加,以解析$name是唯一的最后一个示例:((( 我需要所有这些链接: <?php $mike = mysql_query('SELECT vegetables FROM nature'); while($subfile = mysql_fetch_assoc($mike)) { $jack = $subfile['vegetables']; $name = $jack; }
<?php
$mike = mysql_query('SELECT vegetables FROM nature');
while($subfile = mysql_fetch_assoc($mike))
{
$jack = $subfile['vegetables'];
$name = $jack;
}
//while ends
echo ('<span><a href="index.php?='.$name.'">Vegetables</a>
|
Fruits
|
Suggestions </span>');
?>
将下面的代码放入while循环中
echo ('<span><a href="index.php?='.$name.'">Vegetables</a>
|
Fruits
|
Suggestions </span>');
echo('
|
水果
|
建议);;
假设您希望所有这些都是番茄、黄瓜、沙拉之类的格式,
将它们堆叠在一个数组中,同时在结果上循环,然后将它们粘在一起
<?php
$mike = mysql_query('SELECT vegetables FROM nature');
$names = array();
while($subfile = mysql_fetch_assoc($mike)) {
$jack = $subfile['vegetables'];
$names[] = $jack;
}
//while ends
$list = join(',',$names);
echo ('<span><a href="index.php?='.$list.'">Vegetables</a>
|
Fruits
|
Suggestions </span>');
?>
您正在替换while循环中的相同$name,而不是向其中添加新的蔬菜。这将显示vegetablesvegetablescenets明白吗?我需要蔬菜($name是数据库中的数组,但我不知道如何正确执行foreach或类似操作。)谢谢!这太酷了,我是php新手,所以这种简单性太棒了
<?php
$mike = mysql_query('SELECT vegetables FROM nature');
while($subfile = mysql_fetch_assoc($mike))
{
$name = $subfile['vegetables'];
echo ('<span><a href="index.php?='.$name.'">'.$name.'</a>
|
Fruits
|
Suggestions </span>');
}
//while ends
?>