PHP：如何通过多个匹配值删除数组的特定子数组？

假设我有一个这样的数组：

$cart = [
  [ 'productID' => '11111' , 'size' => 'M' , 'quantity' => 2 ],
  [ 'productID' => '11111' , 'size' => 'L' , 'quantity' => 4 ],
  [ 'productID' => '22222' , 'size' => 'S' , 'quantity' => 3 ],
  [ 'productID' => '22222' , 'size' => 'L' , 'quantity' => 7 ],
  [ 'productID' => '33333' , 'size' => 'M' , 'quantity' => 1 ]
];

现在，我希望能够从数组中删除多个值，如下所示：

removeElementFromArray( $cart , [ 'productID' => '11111' , 'size' => 'M' ] );

但我的问题是我不明白如何实现这一点的逻辑。这就是我所拥有的

function removeElementFromArray($targetArray=[],$needles=[]){

  foreach( $targetArray as $subKey => $subArray ){

    // This is wrong because $removeIt becomes TRUE by any needle matched
    // but I want it to become TRUE only if all $needles match.
    foreach( $needles as $key => $value ){
      if( $subArray[$key] == $value ){
        $removeIt = TRUE;
      }
    }

    // delete row from array
    if( $removeIt == TRUE ){ unset($targetArray[$subKey]); }

  }

  // return
  return $targetArray;

}

---

对代码进行简单的修改就可以了。首先假设您可以删除一个元素，然后如果任何值不匹配，则将其标记为不匹配（并停止查找）

---

超短

array\u filter

版本，带

array\u diff\u assoc

：

function removeElementFromArray($targetArray, $needles) {
    return array_filter($targetArray, function ($item) use ($needles) {
        return !empty(array_diff_assoc($needles, $item));
    });
}

小提琴

function removeElementFromArray($targetArray, $needles) {
    return array_filter($targetArray, function ($item) use ($needles) {
        return !empty(array_diff_assoc($needles, $item));
    });
}