Php 在Laravel中使用一对多关系时尝试获取非对象的属性

因此，当我试图获取创建帖子的用户的姓名时，总是会出现这个错误

我的模型是这样的：

class User extends Authenticatable {
    use Notifiable, CanResetPassword;

    public function posts() {
        return $this->hasMany('App\Post');
    }
}

public function getAdminIndex() {
    $posts = Post::orderBy('id', 'desc')->get();
    $comments = Comment::all();
    $likes = Like::all();
    $users = User::all();

    return view('admin.index', ['posts' => $posts, 'comments' => $comments, 'likes' => $likes, 'users' => $users]);
}

<td>{{ optional($post->user)->name }}</td>

&

我尝试通过在我的视图中执行以下操作来显示名称：

@foreach($posts as $post)
    <tr>
        <td>{{ $post->user->name }}</td>          
    </tr>
@endforeach

谁能告诉我我做错了什么

---

多谢各位

这意味着并非所有帖子都有用户，所以请执行以下操作：

class User extends Authenticatable {
    use Notifiable, CanResetPassword;

    public function posts() {
        return $this->hasMany('App\Post');
    }
}

public function getAdminIndex() {
    $posts = Post::orderBy('id', 'desc')->get();
    $comments = Comment::all();
    $likes = Like::all();
    $users = User::all();

    return view('admin.index', ['posts' => $posts, 'comments' => $comments, 'likes' => $likes, 'users' => $users]);
}

<td>{{ optional($post->user)->name }}</td>

{{可选（$post->user）->name}

或：

{{empty（$post->user）“'No user'：$post->user->name}

这意味着并非所有帖子都有用户，所以请执行以下操作：

class User extends Authenticatable {
    use Notifiable, CanResetPassword;

    public function posts() {
        return $this->hasMany('App\Post');
    }
}

public function getAdminIndex() {
    $posts = Post::orderBy('id', 'desc')->get();
    $comments = Comment::all();
    $likes = Like::all();
    $users = User::all();

    return view('admin.index', ['posts' => $posts, 'comments' => $comments, 'likes' => $likes, 'users' => $users]);
}

<td>{{ optional($post->user)->name }}</td>

{{可选（$post->user）->name}

或：

{{empty（$post->user）“'No user'：$post->user->name}

非常感谢你，我成功了，我会尽快接受你的回答！非常感谢你，任选做了这个把戏，我会尽快接受你的回答！