Php 如何使用ajax获取分页链接(Laravel4.2)

Php 如何使用ajax获取分页链接(Laravel4.2),php,jquery,ajax,laravel-4,laravel-pagination,Php,Jquery,Ajax,Laravel 4,Laravel Pagination,你好 如何传递例如:$transactions->links()在laravel上执行ajax调用时 这是我的控制器在正常情况下的请求: $transactions = DB::table('x_general_transactions') ->whereBetween('x_general_transactions.date_at', array($startDate,$endDate)) ->paginate(30); 看法 根据ajax请求 if (Reque

你好

如何传递
例如:$transactions->links()在laravel上执行ajax调用时

这是我的控制器在正常情况下的请求:

$transactions = DB::table('x_general_transactions')
    ->whereBetween('x_general_transactions.date_at', array($startDate,$endDate))
    ->paginate(30);
看法

根据ajax请求

if (Request::ajax())
    {
        //$divs is my data container
        $res = [$divs,$transactions->links()];
        return Response::json($res);
    }
因此,当我尝试在ajax代码上使用
.load

 $.ajax({
          url: href,
          type: 'get',
          dataType: 'json',
          success: function(response){
            $('.pagination').load(response[1]);
         });
 });
但是什么也没发生,我也试过了

console.log(response[1]);
ajax响应:

[[[{"gt_xid":1230,"gts_xid":1231,"xid":4728,"rnr":4,"code":"OR#","link_code":"CI#","link_rnr":6,"g_type":25,"account_name":"Cash on Hand","debit":50.5,"credit":0,"description":"","date_at":"2015-10-25 16:25:19"},{"gt_xid":1230,"gts_xid":1231,"xid":4729,"rnr":4,"code":"OR#","link_code":"CI#","link_rnr":6,"g_type":25,"account_name":"Accounts Receivable - Trade","debit":0,"credit":50.5,"description":"","date_at":"2015-10-25 16:25:19"}]],{}]

结果:
对象{}`为空。

我希望这有帮助

控制器响应(使用render呈现html并发送响应) ajax代码
希望此代码对您有所帮助

路线: 控制器: 视图(home.ajax.data): 为TestController中的加载数据创建php文件

<div id="content"> 
 <table>
  <tr>
   <td>id</td>
   <td>transaction</td>
   <td>customer</td>
  </tr>
  @foreach($transaction as $key => $val )
  <tr>
   <td>{{ $val->id }}</td>
   <td>{{ $val->transaction }}</td>
   <td>{{ $val->customer }}</td>
  </tr>
  @endforeach
 <tfoot>
  <tr>
   <td colspan="3" align="center">{{ $transaction->links() }}</td>
  </tr>
 </tfoot>
 </table
</div>

REF:

你能发布Ajax的JSON响应吗谢谢你路过先生,我已经更新了上面的问题。你可以检查一下,因为我知道他的方法加载了整个刀片模板,对吗?难道没有办法只加载分页器吗?因为如果是这样的话,我必须重新编码我的大多数视图来应用它,现在分页器链接是唯一正常工作的链接。谢谢你的回答,先生,但是有了这段代码,我仍然得到了
object{}
,这是
console.log(response.links)
helloo。。我的错。。我已经编辑了答案,请查收。很抱歉很晚才回复。。我有事要办。。但是你的答案是最好的!我从昨天开始一直在研究,我不知道我可以使用渲染!xD然后我被迫应用gist.github.com/tobysteward/6163902方法,该方法使我更改了大部分代码。。无论如何,我非常感谢你的好意。。我多么希望你昨天就回答了:)
if (Request::ajax())
{
 $res = array(
  'data' => $divs,
  'links' => $transactions->links()->render()
 );
 return Response::json($res);
}
 $.ajax({
          url: href,
          type: 'get',
          dataType: 'json',
          success: function(response){
             console.log(response.data);//get data
             console.log(response.links);//get links
            $('.pagination').load(response.data);
         });
 });
Route::get('/home/ajax/get','TestController@getAjax');
public function getAjax() {

$transactions = DB::table('x_general_transactions')
    ->whereBetween('x_general_transactions.date_at', array($startDate,$endDate))
    ->paginate(30);
return View::make('home.ajax.data')->with('transaction',$transaction);
}
<div id="content"> 
 <table>
  <tr>
   <td>id</td>
   <td>transaction</td>
   <td>customer</td>
  </tr>
  @foreach($transaction as $key => $val )
  <tr>
   <td>{{ $val->id }}</td>
   <td>{{ $val->transaction }}</td>
   <td>{{ $val->customer }}</td>
  </tr>
  @endforeach
 <tfoot>
  <tr>
   <td colspan="3" align="center">{{ $transaction->links() }}</td>
  </tr>
 </tfoot>
 </table
</div>
<html>
 <head>
  <title>Transaction</title>
 </head>
 <body>
  <div class="box-body table-responsive no-padding">
   @include('home.ajax.data')
  </div>
 </body>
</html>
$(window).on('hashchange',function(){
    page = window.location.hash.replace('#','');
});
$(document).on('click','.pagination a', function(e) {
    e.preventDefault();

    //to get what page, when you click paging
    var page = $(this).attr('href').split('page=')[1];
    //console.log(page);

    getTransaction(page);
    location.hash = page;
});
function getTransaction(page) {

    //console.log('getting sort for page = '+page);
    $.ajax({
        type: 'GET',
        url: '{{URL::to("/home/ajax/get?page=")}}'+page
    }).done(function(data) {
        console.log(data);
        $('#content').html(data);
    });
}