将MySQL查询添加到PHP文件

这是原始的MySQL查询：

 UPDATE jos_bully_table AS jbt1
 INNER
  JOIN ( SELECT jbt2.bully_concat_name,
                COUNT(*) AS b_name_count
           FROM jos_bully_table AS jbt2
          GROUP
             BY jbt2.bully_concat_name
       ) AS jbt3
    ON jbt3.bully_concat_name = jbt1.bully_concat_name
   SET jbt1.b_name_count = jbt3.b_name_count
;

当从phpMyAdmin运行时，它工作得非常好。我单击了创建PHP代码，生成了以下内容：

$sql = "UPDATE jos_bully_table AS jbt1\n"
    . " INNER\n"
    . " JOIN ( SELECT jbt2.bully_concat_name,\n"
    . " COUNT(*) AS b_name_count\n"
    . " FROM jos_bully_table AS jbt2\n"
    . " GROUP\n"
    . " BY jbt2.bully_concat_name\n"
    . " ) AS jbt3\n"
    . " ON jbt3.bully_concat_name = jbt1.bully_concat_name\n"
    . " SET jbt1.b_name_count = jbt3.b_name_count\n"
    . "";

我试图从一个php文件运行相同的查询，但是数据库没有更新

这是我的php文件：

<?php

$database = "xxxxxxxxx" ;
$username = "xxxxxxxxx" ;
$password = "xxxxxxxxx" ;

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");


mysql_query($sql);

$sql = "UPDATE jos_bully_table AS jbt1\n"
    . " INNER\n"
    . " JOIN ( SELECT jbt2.bully_concat_name,\n"
    . " COUNT(*) AS b_name_count\n"
    . " FROM jos_bully_table AS jbt2\n"
    . " GROUP\n"
    . " BY jbt2.bully_concat_name\n"
    . " ) AS jbt3\n"
    . " ON jbt3.bully_concat_name = jbt1.bully_concat_name\n"
    . " SET jbt1.b_name_count = jbt3.b_name_count\n"
    . "";

echo "<!-- SQL Error ".mysql_error()." -->";

?>

---

这有什么问题？

在定义查询字符串之前，您正在运行它

$sql = "SELECT ..."
$result = mysql_query($sql) or die(mysql_error());

此外，请查看用于定义多行字符串的s：

$sql = <<<EOL
SELECT ..
FROM ...
WHERE ...
ORDER BY ..
EOL;

---

$sql=在定义查询字符串之前，您正在运行它

$sql = "SELECT ..."
$result = mysql_query($sql) or die(mysql_error());

此外，请查看用于定义多行字符串的s：

$sql = <<<EOL
SELECT ..
FROM ...
WHERE ...
ORDER BY ..
EOL;

$sql=