Php 什么'；sessionloginid中的代码有什么问题

这是我第一次用php编写代码，我遵循教程。。我希望此代码选择特权表中的所有字段，并检查登录用户的id及其访问级别 但是访问级别并不会随着每个用户的登录而改变

我使用两个表之间的关系，它们是： 特权表

+----------------------------------+
|  AccessLevel | logi_id  | pre_id |
|----------------------------------|
|      1       |    1     |   1    |
|      2       |    1     |   2    | 
|      4       |    2     |   4    |
+----------------------------------+

这是登录预表：

+----------------------------------+
|  username| userpass | login_id   |
|----------------------------------|
|      a   |    123   |   1        |
|      a   |    123   |   1        | 
|      b   |   1234   |   2        |
+----------------------------------+

这是访问页面：

     <?php
        ob_start();
        session_start();
        include 'C:\xampp\htdocs\database\agtdatabase\agt_site\connection\connect.php';
        $query ="SELECT * FROM privilege " ;
        $result = mysqli_query($link,$query) or die('');

            while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
                    {
            $access = $row['AccessLevel'];

                echo $access; //result 124 in database

                        }

            if(isset($_SESSION['sessionloginid']))// point to id of user logged in
            {           
            echo $_SESSION['sessionaccess']=$access;// "that is print  wrong result " access level doesn't change based on user logged in 

            echo $_SESSION['sessionloginid'];

                    }

            ob_end_flush();
        ?>

---

您的查询需要修改。添加一个条件以检索与当前会话['sessionloginid']匹配的访问级别。试试这个：

<?php
      if(isset($_SESSION['sessionloginid']))// point to id of user logged in
        {  
        $query ="SELECT * FROM privilege where logi_id='".$_SESSION['sessionloginid']."'" ;
        $result = mysqli_query($link,$query) or die('');
        while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
                {
        $access = $row['AccessLevel'];

            echo $_SESSION['sessionaccess']=$access;
            echo $_SESSION['sessionloginid'];
                    }
                }

        ob_end_flush();
    ?>

---

因此，您希望检索登录用户的访问级别？？？。例如：登录id为
1
的用户应显示访问级别
12
。是这样吗？为什么不在查找用户名和密码时进行连接以获得结果权限？
<?php
      if(isset($_SESSION['sessionloginid']))// point to id of user logged in
        {  
        $query ="SELECT * FROM privilege where logi_id='".$_SESSION['sessionloginid']."'" ;
        $result = mysqli_query($link,$query) or die('');
        while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
                {
        $access = $row['AccessLevel'];

            echo $_SESSION['sessionaccess']=$access;
            echo $_SESSION['sessionloginid'];
                    }
                }

        ob_end_flush();
    ?>