Php 不能通过以下方式绑定订单？

我试图绑定ORDER BY的值，使其具有按分数或添加日期排序的选项，但是，当我尝试绑定ORDER BY值时，它将返回到标准的ORDER BY id，并且不听取我的命令

下面是我的代码，我已将查询中的分数部分替换为？给了它一个值，但它不起作用

<?php
include("config.php");
$page_number = filter_var($_POST["page"], FILTER_SANITIZE_NUMBER_INT, FILTER_FLAG_STRIP_HIGH);

if(!is_numeric($page_number)){
  header('HTTP/1.1 500 Invalid page number!');
  exit();
}
session_start();
$position = (($page_number-1) * $item_per_page);
$search = "%{$_SESSION['search']}%";
$city = $_SESSION['city'];
if(isset($_SESSION['type'])){
  $typesql = $_SESSION['type'];
}
if(isset($_SESSION['type2'])){
  $typesql2 = $_SESSION['type2'];
}
if(empty($_SESSION['type']) && empty($_SESSION['type2'])){
  $typesql = 'photographer';
  $typesql2 = 'makeup artist';
}
if($city=='Alexandria' || $city=='Cairo'){
$results = $mysqli->prepare("SELECT name, location, score, img, id, type FROM artists WHERE CONCAT(name, location) LIKE ? AND visible='yes' AND type IN(?, ?) AND location IN(?) ORDER BY score  DESC LIMIT ?, ?");
$results->bind_param("ssssii", $search, $typesql, $typesql2, $city, $position, $item_per_page);
}else{
  $results = $mysqli->prepare("SELECT name, location, score, img, id, type FROM artists WHERE CONCAT(name, location) LIKE ? AND visible='yes' AND type IN(?, ?) ORDER BY score  DESC LIMIT ?, ?");
  $results->bind_param("sssii", $search, $typesql, $typesql2, $position, $item_per_page);
}



$results->execute();
$results->bind_result($name, $location, $score, $img, $id, $type);

// Le fetch
  while($results->fetch()){
    echo  "<div class=\"card feed_item\" style=\"width: 20rem;\"><a id=\"wraplink\" href=\"profile.php?id=". $id."\">";
    echo  "<div class=\"imgcont\"><img class=\"card-img-top feed_img\" src=\"img/" . $img . ".jpg\"></div>";
    echo  "<div class=\"card-block\">";
    echo  "<h4 class=\"card-title\">" . $name . "</h4>";;
    echo  "</div><div class=\"card-footer ";
    if($type=="Photographer"){
      echo "footerph";
    }else{
      echo "footermk";
    }
    echo  "\"><small class=\"text-muted\"><b>". $type;
    if($city=="Egypt"){
      echo " from ". $location;
    }
    echo  "</b></small><span class=\"fb-comments-count\" data-href=\"http://setch.me/profile.php?id=".$id."\"></span></div></a></div>";
  }
  ?>

---

to bind ORDER by's value”的确切含义是什么？您不能使用
bind_param（）
来绑定列名。您应该使用PDO，而不是mysqli。但是，您还试图将6个参数绑定到4个占位符。}else{$results=$mysqli->prepare（“选择名称、位置、分数、img、id，从艺术家那里输入，其中CONCAT（名称、位置）类似于？和visible='yes'，并按分数描述限制的顺序键入？”）；$results->bind_参数（“sssii”、$search、$typesql、$typesql2、$position、$item_per_page）；）很高兴看到php代码看起来仍然和15年前一样。