PHP数组中的歧义

我想显示developer.ean.com API中的行程详细信息。通过传递客户的行程ID和电子邮件ID，我得到了预订的详细信息。 结果是以json格式提交，因此我对其进行了解码，并使用以下方法创建了数组：

$array=json_decode($result);

问题在于API产生的任何结果都包含以下问题：

对于某些记录，它提供如下数组：

[Itinerary] => stdClass Object
        (
            [HotelConfirmation] => Array
                (
                    [0] => stdClass Object
                        (
                            [supplierId] => 13
                            [chainCode] => EP
                            [arrivalDate] => 07/24/2012
                            [departureDate] => 07/26/2012
            )
            [Hotel] => Array
                        (
                            [0] => stdClass Object
                                (
                                   [hotelId] => 394808
                                   [statusCode] => A
                                   [name] => Barkston Youth Hostel
                )
            )
        )
    )

[Itinerary] => stdClass Object
        (
            [HotelConfirmation] => stdClass Object
                (
                            [supplierId] => 13
                            [chainCode] => EP
                            [arrivalDate] => 07/24/2012
                            [departureDate] => 07/26/2012
            )
       [Hotel] => stdClass Object              
                (
                            [hotelId] => 394808
                            [statusCode] => A
                            [name] => Barkston Youth Hostel
            )
       )

if (isset($array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'][0])) {
    $array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'] = $array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'][0];
}

在这种情况下，HotelConfirmation和Hotel是包含[0]作为对象的数组

对于某些记录，它提供如下数组：

[Itinerary] => stdClass Object
        (
            [HotelConfirmation] => Array
                (
                    [0] => stdClass Object
                        (
                            [supplierId] => 13
                            [chainCode] => EP
                            [arrivalDate] => 07/24/2012
                            [departureDate] => 07/26/2012
            )
            [Hotel] => Array
                        (
                            [0] => stdClass Object
                                (
                                   [hotelId] => 394808
                                   [statusCode] => A
                                   [name] => Barkston Youth Hostel
                )
            )
        )
    )

[Itinerary] => stdClass Object
        (
            [HotelConfirmation] => stdClass Object
                (
                            [supplierId] => 13
                            [chainCode] => EP
                            [arrivalDate] => 07/24/2012
                            [departureDate] => 07/26/2012
            )
       [Hotel] => stdClass Object              
                (
                            [hotelId] => 394808
                            [statusCode] => A
                            [name] => Barkston Youth Hostel
            )
       )

if (isset($array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'][0])) {
    $array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'] = $array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'][0];
}

在这种情况下，酒店确认和酒店本身就是一个对象

我在这里只提供了很少的数据，实际上是它的大数组，我想提供它的列表。但是数组包含这样的模糊性。我如何处理这个问题。有什么解决办法吗

提前感谢。

您可以使用

is\u array（）

检查它：

if (is_array($hotel)) {
    $hotel = $hotel[0];
}

---

检查对象或数组：

if( is_object($Itinerary -> HotelConfirmation)) {
// do one thing or nothing
} elseif( is_array($Itinerary -> HotelConfirmation)) {
$Itinerary -> HotelConfirmation = array_shift( $Itinerary -> HotelConfirmation );
}

---

将

true

作为第二个参数传递给

json\u decode

。这将创建一个数组，而不是

stdClass

$array=json_decode($result, true);

换个说法：

$array=json_decode($result,TRUE);

---

是否始终处理数组？

看起来您可能需要考虑模型中的两种可能性。。。检查hotel节点是否包含and数组或obj，并相应地进行操作

可以在数组中键入case对象

$array = json_decode($result);
$array = (array)$array

或者，您也可以将true作为json_decode（）中的第二个参数传递

根据php文档

When TRUE, returned objects will be converted into associative arrays.

---

您可以像这样规范化输入：

// get objects as arrays
$array = json_decode($result, true);
// remove the sub-level [0], when necessary
foreach ($array as $key => $value) {
    if (is_array($value[0])) {
        $array[$key] = $value[0];
    }
}

那么结果看起来总是一样的：

[Itinerary] => Array
        (
            [HotelConfirmation] => Array
                (
                            [supplierId] => 13
                            [chainCode] => EP
                            [arrivalDate] => 07/24/2012
                            [departureDate] => 07/26/2012
            )
            [Hotel] => Array              
                (
                            [hotelId] => 394808
                            [statusCode] => A
                            [name] => Barkston Youth Hostel
            )
       )

首先要做到：

$array = json_decode($result, true);

这样做：

[Itinerary] => stdClass Object
        (
            [HotelConfirmation] => Array
                (
                    [0] => stdClass Object
                        (
                            [supplierId] => 13
                            [chainCode] => EP
                            [arrivalDate] => 07/24/2012
                            [departureDate] => 07/26/2012
            )
            [Hotel] => Array
                        (
                            [0] => stdClass Object
                                (
                                   [hotelId] => 394808
                                   [statusCode] => A
                                   [name] => Barkston Youth Hostel
                )
            )
        )
    )

[Itinerary] => stdClass Object
        (
            [HotelConfirmation] => stdClass Object
                (
                            [supplierId] => 13
                            [chainCode] => EP
                            [arrivalDate] => 07/24/2012
                            [departureDate] => 07/26/2012
            )
       [Hotel] => stdClass Object              
                (
                            [hotelId] => 394808
                            [statusCode] => A
                            [name] => Barkston Youth Hostel
            )
       )

if (isset($array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'][0])) {
    $array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'] = $array['HotelItineraryResponse']['Itinerary']['HotelConfirmation'][0];
}

---

它肯定会起作用。

您最初的json字符串是什么？有时类似于

HotelConfirmation:{“supplierId”：13}

有时类似于

HotelConfirmation:[{“supplierId”：13}]

每一种情况发生时有什么模式吗？没有任何一种情况发生record@Kunal：你能在某个地方发布一个完整的JSON结果以便我测试吗？谢谢…实际上我在你代码的帮助下做了一些调整…非常感谢兄弟