是否使用php打印下拉列表中的选定值?
我试图在下拉列表中打印所选值,但徒劳。我不熟悉php和html,所以这听起来可能是个愚蠢的问题,但请帮助我!这是我的代码:是否使用php打印下拉列表中的选定值?,php,html,Php,Html,我试图在下拉列表中打印所选值,但徒劳。我不熟悉php和html,所以这听起来可能是个愚蠢的问题,但请帮助我!这是我的代码: echo '<tr><td>Client:</td><td><select name="client_name">'; $sql = mysql_query("SELECT * FROM client"); $s= mysql_query("SELECT pro
echo '<tr><td>Client:</td><td><select name="client_name">';
$sql = mysql_query("SELECT * FROM client");
$s= mysql_query("SELECT project.client_id, client_name, client.client_id FROM client,project where project.client_id=client.client_id AND project_id='$editId'");
// $s2= mysql_fetch_array($s);
while ($row = mysql_fetch_array($sql))
{
while ($s2==mysql_fetch_array($s))
{
if ($row['client_id'] == $s2['client_id'])
$selected = "selected=\"selected\"";
else
$selected = " ";
}
echo '<option value="' . $row['client_id'] . '" ' . ($selected == $row['client_id'] ? ' selected' : '') . '>' . $s2['client_name'] . '</option>';
}
echo“客户端:”;
$sql=mysql_查询(“从客户端选择*);
$s=mysql\u查询(“从客户端选择project.client\u id,客户端名称,客户端.client\u id,project where project.client\u id=client.client\u id,project\u id='$editId');
//$s2=mysql\u fetch\u数组($s);
while($row=mysql\u fetch\u数组($sql))
{
而($s2==mysql\u fetch\u数组($s))
{
如果($row['client\u id']=$s2['client\u id']))
$selected=“selected=\”selected\”;
其他的
$selected=“”;
}
回显'.$s2['client_name'].';
}
这个代码不起作用。请帮帮我!有其他方法吗?试试这个
echo '<tr><td>Client:</td><td><select name="client_name">';
$sql = mysql_query("SELECT * FROM client");
$s= mysql_query("SELECT project.client_id, client_name, client.client_id FROM client,project where project.client_id=client.client_id AND project_id='$editId'");
// $s2= mysql_fetch_array($s);
while ($row = mysql_fetch_array($sql))
{
while ($s2==mysql_fetch_array($s))
{
if ($row['client_id'] == $s2['client_id'])
$selected = "selected=\"selected\"";
else
$selected = " ";
}
echo '<option value="' . $row['client_id'] . '" ' . $selected . '>' . $s2['client_name'] . '</option>';
}`
echo“客户端:”;
$sql=mysql_查询(“从客户端选择*);
$s=mysql\u查询(“从客户端选择project.client\u id,客户端名称,客户端.client\u id,project where project.client\u id=client.client\u id,project\u id='$editId');
//$s2=mysql\u fetch\u数组($s);
while($row=mysql\u fetch\u数组($sql))
{
而($s2==mysql\u fetch\u数组($s))
{
如果($row['client\u id']=$s2['client\u id']))
$selected=“selected=\”selected\”;
其他的
$selected=“”;
}
回显'.$s2['client_name'].';
}`
此查询是一个问题
$s= mysql_query("SELECT project.client_id, client_name, client.client_id FROM client,project where project.client_id=client.client_id AND project_id='$editId'");
您正在尝试获取两个客户端id project.client\u id和client.client\u id,在这种情况下,您应该将类似project.client\u id的别名指定为project\u client\u id,将client.client\u id指定为client\u id,然后使用该值在while循环中进行比较
注意:使用您想要的任何客户id,无论是project\u client\u id还是client\u client\u id。“此代码不起作用。”没有多大帮助。它在做什么?应该做什么?$s2似乎没有初始化。请再次检查您的代码,并上传