PHP上载多个文件仅上载1个文件
我多次编辑这段代码(imnoobwhitphp),我的问题是用这段代码上传多个文件。我只能上传一个文件 代码如下:PHP上载多个文件仅上载1个文件,php,upload,Php,Upload,我多次编辑这段代码(imnoobwhitphp),我的问题是用这段代码上传多个文件。我只能上传一个文件 代码如下: <?php /** * uploadFile() * * @param string $file_field name of file upload field in html form * @param bool $check_image check if uploaded file is a valid image * @param bool $random_
<?php
/**
* uploadFile()
*
* @param string $file_field name of file upload field in html form
* @param bool $check_image check if uploaded file is a valid image
* @param bool $random_name generate random filename for uploaded file
* @return array
*/
function uploadFile ($file_field = null, $check_image = false, $random_name = false) {
//Config Section
//Set file upload path
$path = 'c:/xampp/htdocs/'; //with trailing slash
//Set max file size in bytes
$max_size = 1000000;
//Set default file extension whitelist
$whitelist_ext = array('jpg','png','gif');
//Set default file type whitelist
$whitelist_type = array('image/jpeg', 'image/png','image/gif');
//The Validation
// Create an array to hold any output
$out = array('error'=>null);
if (!$file_field) {
$out['error'][] = "Please specify a valid form field name";
}
if (!$path) {
$out['error'][] = "Please specify a valid upload path";
}
if (count($out['error'])>0) {
return $out;
}
//Make sure that there is a file
if((!empty($_FILES[$file_field])) && ($_FILES[$file_field]['error'] == 0)) {
// Get filename
$file_info = pathinfo($_FILES[$file_field]['name']);
$name = $file_info['filename'];
$ext = $file_info['extension'];
//Check file has the right extension
if (!in_array($ext, $whitelist_ext)) {
$out['error'][] = "Invalid file Extension";
}
//Check that the file is of the right type
if (!in_array($_FILES[$file_field]["type"], $whitelist_type)) {
$out['error'][] = "Invalid file Type";
}
//Check that the file is not too big
if ($_FILES[$file_field]["size"] > $max_size) {
$out['error'][] = "File is too big";
}
//If $check image is set as true
if ($check_image) {
if (!getimagesize($_FILES[$file_field]['tmp_name'])) {
$out['error'][] = "Uploaded file is not a valid image";
}
}
//Create full filename including path
if ($random_name) {
// Generate random filename
$tmp = str_replace(array('.',' '), array('',''), microtime());
if (!$tmp || $tmp == '') {
$out['error'][] = "File must have a name";
}
$newname = $tmp.'.'.$ext;
} else {
$newname = $name.'.'.$ext;
}
//Check if file already exists on server
if (file_exists($path.$newname)) {
$out['error'][] = "A file with this name already exists";
}
if (count($out['error'])>0) {
//The file has not correctly validated
return $out;
}
if (move_uploaded_file($_FILES[$file_field]['tmp_name'], $path.$newname)) {
//Success
$out['filepath'] = $path;
$out['filename'] = $newname;
return $out;
} else {
$out['error'][] = "Server Error!";
}
} else {
$out['error'][] = "No file uploaded";
return $out;
}
}
?>
<?php
if (isset($_POST['submit'])) {
$file = uploadFile('file', true, true);
if (is_array($file['error'])) {
$message = '';
foreach ($file['error'] as $msg) {
$message .= '<p>'.$msg.'</p>';
}
} else {
$message = "File uploaded successfully";
}
echo $message;
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<input name="file" type="file" size="20" multiple="multiple" />
<input name="submit" type="submit" value="Upload files" />
</form>
您必须使用foreach循环上载多个文件。在框架中,您还提供了具有相同功能的组件(即通过使用foreach循环) 您应该使用file字段作为数组,如file[]
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<input name="file[]" type="file" size="20" multiple="multiple" />
<input name="submit" type="submit" value="Upload files" />
</form>
正如其他人所指出的,您需要将上载字段名更改为ie.files[](名称后面包括sqaure括号)。这是相关的,因为它告诉PHP应该将字段视为数组
此外,在代码中,您可以使用foreach()访问上传的文件,如下所示:
foreach ($_FILES['field_name'] as $file)
["name"]=>
array(2) {
[0]=>
string(5) "dir.c"
[1]=>
string(10) "errcodes.h"
}
["type"]=>
array(2) {
[0]=>
string(11) "text/x-csrc"
[1]=>
string(11) "text/x-chdr"
}
["tmp_name"]=>
array(2) {
[0]=>
string(14) "/tmp/phpP1iz5A"
[1]=>
string(14) "/tmp/phpf31fzn"
}
["error"]=>
array(2) {
[0]=>
int(0)
[1]=>
int(0)
}
["size"]=>
array(2) {
[0]=>
int(511)
[1]=>
int(38)
}
}
(显然,在本例中,yout html字段将是names字段_name[]
这将在五次迭代中每次返回一个数组,为您提供有关已发送的所有文件的信息。例如,如果您发送了两个文件,则可能如下所示:
foreach ($_FILES['field_name'] as $file)
["name"]=>
array(2) {
[0]=>
string(5) "dir.c"
[1]=>
string(10) "errcodes.h"
}
["type"]=>
array(2) {
[0]=>
string(11) "text/x-csrc"
[1]=>
string(11) "text/x-chdr"
}
["tmp_name"]=>
array(2) {
[0]=>
string(14) "/tmp/phpP1iz5A"
[1]=>
string(14) "/tmp/phpf31fzn"
}
["error"]=>
array(2) {
[0]=>
int(0)
[1]=>
int(0)
}
["size"]=>
array(2) {
[0]=>
int(511)
[1]=>
int(38)
}
}
重要的是要理解,PHP不会将这些文件分类,然后为每个文件提供属性,而是列出所有文件的属性
我希望现在清楚了。我的建议是
启动一个循环:foreach($\u FILES[$file\u field]作为$file){
在函数末尾用}
将其关闭
将其中的所有$\u文件[$file\u字段]
更改为$file
当然,输入必须具有multiple
属性,如Sherin Josesaid(),但现在它只受多个浏览器的完全支持,所以最好用JS添加更多输入,如
<input type="file" name="file[]" />
<input type="file" name="file[]" />
...
...
并以相同的方式循环它们要从浏览器成功发送多个文件,需要输入将数组传递给PHP。这是通过将[]
附加到您的
姓名的末尾来完成的:
<input type="file" name="filesToUpload[]" multiple>
要运行此示例,您的文件应该如下所示
您可以使用以下命令启动PHP内置Web服务器:
$ php -S localhost:8000
然后将运行该示例
重要注意事项:上述示例不进行任何验证。您需要验证所有上传的文件是否安全。multiple仍然不需要完全是HTML5的multiple=“multiple”
只有multiple
就足够了,您还可以对同名的多个字段使用[]
,但您不需要它,当您仅对1个字段使用multiple
属性时,但我认为您不会获得所有文件,只会生成一个文件..尝试一下..这次您是对的,但很困惑,为什么要使用两个修改?看起来像是HTML5 BugMultiple属性仅用于使用单个文件字段保存多个文件,但如果没有数组类型,php总是将其作为单个文件处理。。。