Php pdo rollBack（）不适用于update语句

我使用PHP PDO事务。我有insert和update语句，我想在rowCount（）返回0时回滚事务。请参阅下面的示例代码

<?php
$pdo = new PDO('mysql:host=localhost;dbname=test', 'root', '', array(
    PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_EMULATE_PREPARES => false
));

$userIds = [1,2,""];
$paymentAmounts = [10.50,20.50,30.50];
$error = array();

$pdo->beginTransaction();

try
{
    foreach($userIds as $key => $userId )
    {
        $sql = "INSERT INTO payments (user_id, amount) VALUES (?, ?)";
        $stmt = $pdo->prepare($sql);
        $stmt->execute(array(
                $userId, 
                $paymentAmounts[$key]
            )
        );

        if($stmt->rowCount() <= 0)
        {
            $error[] = ["Error occurred in userId: ".$userId];
        }

        $sql = "UPDATE users SET credit = ? WHERE id = ?";
        $stmt = $pdo->prepare($sql);
        $stmt->execute(array(
                $paymentAmounts[$key],
                $userId
            )
        );
        if($stmt->rowCount() <= 0)
        {
            $error[] = ["Error occurred in userId: ".$userId];
        }
    }
    if(!empty($error))
    {
        $displayError = implode(",", $error);
        throw new Exception($displayError);
    }

    // It should not reach here, if there is an error.
    $pdo->commit();

}
catch(Exception $e){
    echo $e->getMessage(); // displayError
    $pdo->rollBack(); // <<<==== It should rollback both Insert and Update to original state
}
?>

测试后#1

测试#2~故意导致异常-使用以下数据的数组长度不匹配：

        $userIds = array(1,2,3,4,5,6);
        $paymentAmounts = array( 25,30,55,30,45,44,21 );/* <----- extra item to cause exception */

与以前相同的数据-异常后查询未提交到db

测试#3-伪造列名的查询

$sql = "update users set credit = boomerang + ? where id = ?";/* <----- ficticious column cause exception */

---

同样，快速检查显示数据没有变化，因此整个过程看起来都正常运行

您的代码应该包括一个表创建查询和一个插入查询来填充它，这样每个人都可以确认该行为。不过，这是一个疯狂的猜测。你的用户表引擎真的是InnoDB吗？是的，它是InnoDB。谢谢你的回复。我已经添加了表和插入查询。你应该提供打算一次运行的完整代码。让一个人只是复制粘贴它，然后得到结果。但是请确保您事先自己运行它，它实际上支持您的说法，即某些表没有回滚，这是为了抛出一个异常——一对故意不匹配的数组。我只是在我这边进行了测试。更新仍然不会还原为原始数据。你能换这条线吗？From$sql=“updateusers set credit=credit+，其中id=？”$paymentAmounts=数组（25,30,55,30,45,44,21）；To$sql=“更新用户设置信用=？其中id=？”$付款金额=数组（40,90,15,30,45,44,21）；

mysql> select * from payments;
Empty set (0.00 sec)

mysql> select * from users;
+------+--------+
| id   | credit |
+------+--------+
|    1 | 0      |
|    2 | 0      |
|    3 | 0      |
|    4 | 0      |
|    5 | 0      |
|    6 | 0      |
+------+--------+
6 rows in set (0.00 sec)

mysql> select * from payments;
+----+---------+--------+
| id | user_id | amount |
+----+---------+--------+
|  1 |       1 | 25     |
|  2 |       2 | 30     |
|  3 |       3 | 55     |
|  4 |       4 | 30     |
|  5 |       5 | 45     |
|  6 |       6 | 44     |
+----+---------+--------+
6 rows in set (0.00 sec)

mysql> select * from users;
+------+--------+
| id   | credit |
+------+--------+
|    1 | 25     |
|    2 | 30     |
|    3 | 55     |
|    4 | 30     |
|    5 | 45     |
|    6 | 44     |
+------+--------+
7 rows in set (0.00 sec)

        $userIds = array(1,2,3,4,5,6);
        $paymentAmounts = array( 25,30,55,30,45,44,21 );/* <----- extra item to cause exception */

Exception Raised: Unbalanced source arrays: $userids:6, $paymentAmounts:7

mysql> select * from users;
+----+--------+
| id | credit |
+----+--------+
|  1 | 25     |
|  2 | 30     |
|  3 | 55     |
|  4 | 30     |
|  5 | 45     |
|  6 | 44     |
+----+--------+
6 rows in set (0.00 sec)

$sql = "update users set credit = boomerang + ? where id = ?";/* <----- ficticious column cause exception */

Exception Raised: Query #2 -> Error occurred in userId: 1 count: 0

mysql> select * from users;
+----+--------+
| id | credit |
+----+--------+
|  1 | 25     |
|  2 | 30     |
|  3 | 55     |
|  4 | 30     |
|  5 | 45     |
|  6 | 44     |
+----+--------+
6 rows in set (0.00 sec)