如何使用php从mysql获取表名和列?
我在mySQL中创建了一个连接表,如下所示如何使用php从mysql获取表名和列?,php,mysql,Php,Mysql,我在mySQL中创建了一个连接表,如下所示 SELECT junction_departments_qsps.departments_fk, junction_departments_qsps.checked, qsps.id, qsps.qsp_name, employees.id, employees.first_name, employees.last_name FROM junction_departments_qsps INNER JOIN qsps ON junction_d
SELECT junction_departments_qsps.departments_fk, junction_departments_qsps.checked, qsps.id, qsps.qsp_name, employees.id, employees.first_name, employees.last_name
FROM junction_departments_qsps
INNER JOIN qsps ON junction_departments_qsps.qsps_fk = qsps.id
INNER JOIN employees ON employees.department_id = junction_departments_qsps.departments_fk
WHERE junction_departments_qsps.checked = 1
正如您所看到的,我有几个表具有相同的列名“id”。在mySQL中,将表名链接到列名,如table-name.column-name。在PHP中,我通常通过创建一个循环然后进行回音来获得列名
$variable["column-name"];
PHP中有没有像mySQL中那样获得表名和列名的方法?我试过这个
$variable["table-name.column-name"];
它不起作用
我的联接表的问题是当我这样做时
$variable["id"];
我没有得到正确的id,因为mySQL中要求我有多个id
非常感谢您的帮助!:) 您可以使用别名语法:
SELECT `id` as `object_id` FROM `objects`
我不知道MySQL是否喜欢别名中的
,如果喜欢,那就太好了 如果在不同的表中有相同的列名,则可以在查询中使用AS,例如
select a.id AS ida, b.id AS idb FROM tab1 a join tab2 b using(column)
在结果上你比
$data['ida];
$data['idb'];
junction\u departments\u qsps.departments\u fk作为junction\u departments\u qsps\u departments\u fk