有没有一种方法可以处理来自php artisan make:request发出的请求的响应?
我收到Laravel wit FormRequest extend的请求,并附上以下规则和信息:有没有一种方法可以处理来自php artisan make:request发出的请求的响应?,php,laravel,exception,python-requests,httpresponse,Php,Laravel,Exception,Python Requests,Httpresponse,我收到Laravel wit FormRequest extend的请求,并附上以下规则和信息: public function rules() { return [ 'login' => 'required', 'password' => 'required', ]; } public function messages() { return [ 'login:required' => 'Login i
public function rules()
{
return [
'login' => 'required',
'password' => 'required',
];
}
public function messages()
{
return [
'login:required' => 'Login is required',
'password:required' => 'Password is required'
];
}
现在我收到了这样的回复:
{
"message": "The given data was invalid.",
"errors": {
"login": [
"The login field is required."
],
"password": [
"The password field is required."
]
}
}
但我想要这样的东西:
{
"status": false,
"validator": true,
"msg": {
"e": {
"login": [
"The login field is required."
],
"password": [
"The password field is required."
]
},
"type": "error"
}
}
这可能吗
因为现在我用这个代码来得到:
$item = Validator::make($request->all(), [
'login' => 'required',
'password' => 'required',
]);
if ($item->fails())
return response()->json([
'status' => false,
'validator' => true,
'msg' => [
'e' => $item->messages(),
'type' => 'error'
],
]);
但是我想根据larave提出的请求(php artisan make:Request)是的,您可以这样做。将此方法添加到表单请求类:
use Illuminate\Contracts\Validation\Validator;
use Illuminate\Http\Exceptions\HttpResponseException;
// ...
protected function failedValidation(Validator $validator)
{
$data = [
'status' => false,
'validator' => true,
'msg' => [
'e' => $validator->errors(),
'type' => 'error',
],
];
throw new HttpResponseException(response()->json($data, 422));
}
我得到这样的回应:
{“消息”:“服务器错误”}
@Marius my bad。请用我更新的答案再试一次。我已经测试过了,效果很好。