Php MSSQL Multi-SELECT FROM 4表格（如何？）

当我获取aasoc时，我需要从其他表中选择4。这是非常糟糕的和停止驱动器页。 请告诉我，有可能提出一个而不是四个请求吗

$sql_id_city = "SELECT * FROM City WHERE id_city='$id_city'";
$get_id_city = sqlsrv_query($conn, $sql_id_city);
$info_id_city = sqlsrv_fetch_array($get_id_city, SQLSRV_FETCH_ASSOC); 
$name_city=$info_id_city['name'];


$id_producer_country=($i['id_producer_country']!='')? $i['id_producer_country']:'0';

$sql_id_producer_country = "SELECT * FROM Producer_country WHERE id_producer_country='$id_producer_country'";
$get_id_producer_country = sqlsrv_query($conn, $sql_id_producer_country);
$info_producer_country = sqlsrv_fetch_array($get_id_producer_country, SQLSRV_FETCH_ASSOC);
$name_producer_country=$info_producer_country['name'];



$id_firm=($i['id_firm']!='')? $i['id_firm']:'0';

$sql_id_firm = "SELECT * FROM Firm WHERE id_firm='$id_firm'";
$get_id_firm = sqlsrv_query($conn, $sql_id_firm);
$info_film = sqlsrv_fetch_array($get_id_firm, SQLSRV_FETCH_ASSOC);
$name_firm=$info_film['name'];
$phone_firm=$info_film['phone'];

$id_price=($i['id_price']!='')? $i['id_price']:'0';

$sql_id_cost = "SELECT * FROM Cost WHERE id_price='$id_price'";
$get_id_cost = sqlsrv_query($conn, $sql_id_cost);
$info_cost = sqlsrv_fetch_array($get_id_cost, SQLSRV_FETCH_ASSOC);
$cost=$info_cost['cost'];
$id_currency=$info_cost['id_currency'];
$id_sale=$info_cost['id_sale'];

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令人不快的此选项显示表中的所有行，条件是City.id\u City='$id\u City'和Producer\u country.id\u Producer\u country=City.'$id\u Producer\u country id作为City表中的字段'和Firm.id\u Firm='$id\u firmfiels name作为Producer\u country表中的u'和Cost.id\u price='$id\u pricefiels name作为Firm表中的u，您能详细介绍一下吗？

    "SELECT * FROM City , Producer_country , Firm , Cost WHERE City.id_city='$id_city'
 AND Producer_country.id_producer_country=City.'$id_producer_country(country id as field in city table)' 
AND Firm.id_firm='$id_firm(fiels name as u in Producer_country table )' AND
 Cost.id_price='$id_price(fiels name as u in firm table)'"


if u have same as fiels in other table so u can use the as keyword for avoid the ambiguity