Php 拉威尔怎么能得到这种关系

考虑一个

数字商店

定义：

Buyer->all buyer
Products->all products
Downloads->store those products that buyer bought

-----------------------
|id | name  | seller_id  |
-----------------------
| 1 | bmw   |    1     |
-----------------------
| 2 | benz  |    1     |
-----------------------
| 2 | reno  |    2     |
-----------------------

------------------------------
|id | product_id  | buyer_id  |
------------------------------
| 1 |     1     |      1      |
------------------------------
| 2 |     1     |      2      |
------------------------------
| 3 |     2     |      22     |
------------------------------

------------------------------
|id | name     |       email  |
------------------------------
| 1 |     john     |      @   |
------------------------------
| 2 |     mike     |      @   |
------------------------------
| 3 |     dave     |      @  |
------------------------------

买家

可以购买

产品

并将其存储在

下载中

，现在我想向买家显示下载列表

ProductController.php

public function buyerproducts()
{
    $user = auth()->guard('buyer')->user();
    if ($user) {
        $files = Product::where('deleted', 0)
            ->where('deleted', 0)
            ->with('files', 'province:id,name', 'city:id,name')
            ->get();

        // and here I got a loop.. to add some extra data
        return response()->json(['data' => $files], 200);
    } else {
        return response()->json(['success' => 'no content'], 204);
    }
}

function files()
{
    return $this->hasManyThrough('App\Download', 'App\Buyer', 'id', 'product_id', 'buyer_id', 'id');
}

Product.php

public function buyerproducts()
{
    $user = auth()->guard('buyer')->user();
    if ($user) {
        $files = Product::where('deleted', 0)
            ->where('deleted', 0)
            ->with('files', 'province:id,name', 'city:id,name')
            ->get();

        // and here I got a loop.. to add some extra data
        return response()->json(['data' => $files], 200);
    } else {
        return response()->json(['success' => 'no content'], 204);
    }
}

function files()
{
    return $this->hasManyThrough('App\Download', 'App\Buyer', 'id', 'product_id', 'buyer_id', 'id');
}

但它会返回所有数据，而不是买家购买的数据。有什么想法吗？ 请注意，我必须在product controller中获取此数据，而不是下载

---

产品：

Buyer->all buyer
Products->all products
Downloads->store those products that buyer bought

-----------------------
|id | name  | seller_id  |
-----------------------
| 1 | bmw   |    1     |
-----------------------
| 2 | benz  |    1     |
-----------------------
| 2 | reno  |    2     |
-----------------------

------------------------------
|id | product_id  | buyer_id  |
------------------------------
| 1 |     1     |      1      |
------------------------------
| 2 |     1     |      2      |
------------------------------
| 3 |     2     |      22     |
------------------------------

------------------------------
|id | name     |       email  |
------------------------------
| 1 |     john     |      @   |
------------------------------
| 2 |     mike     |      @   |
------------------------------
| 3 |     dave     |      @  |
------------------------------

下载：

Buyer->all buyer
Products->all products
Downloads->store those products that buyer bought

-----------------------
|id | name  | seller_id  |
-----------------------
| 1 | bmw   |    1     |
-----------------------
| 2 | benz  |    1     |
-----------------------
| 2 | reno  |    2     |
-----------------------

------------------------------
|id | product_id  | buyer_id  |
------------------------------
| 1 |     1     |      1      |
------------------------------
| 2 |     1     |      2      |
------------------------------
| 3 |     2     |      22     |
------------------------------

------------------------------
|id | name     |       email  |
------------------------------
| 1 |     john     |      @   |
------------------------------
| 2 |     mike     |      @   |
------------------------------
| 3 |     dave     |      @  |
------------------------------

买方：

Buyer->all buyer
Products->all products
Downloads->store those products that buyer bought

-----------------------
|id | name  | seller_id  |
-----------------------
| 1 | bmw   |    1     |
-----------------------
| 2 | benz  |    1     |
-----------------------
| 2 | reno  |    2     |
-----------------------

------------------------------
|id | product_id  | buyer_id  |
------------------------------
| 1 |     1     |      1      |
------------------------------
| 2 |     1     |      2      |
------------------------------
| 3 |     2     |      22     |
------------------------------

------------------------------
|id | name     |       email  |
------------------------------
| 1 |     john     |      @   |
------------------------------
| 2 |     mike     |      @   |
------------------------------
| 3 |     dave     |      @  |
------------------------------

---

HasManyThrough

关系将经历2个

hasMany

关系，但是，查看表定义，第一个关系是

hasMany

，第二个关系是

belongsTo

。由于两个键都与不同表中的一行相关（都是

belongsTo

），因此我们可以改为创建

belongstomy

关系，并将

downloads

表作为轴心

---

有两种不同的方法可以解决这个问题

首先，我建议在

买家

和

产品

之间建立关系（您是否还没有这样做）：

产品

public function buyers()
{
    return $this->belongsToMany(Buyer::class, 'downloads')->withTimestamps();
}

买方

public function products()
{
    return $this->belongsToMany(Product::class, 'downloads')->withTimestamps();
}

---

然后，在控制器方法中，您可以保留相同的查询并使用：

或或者，您不能直接从

$user

（买方）查询产品：

---

你为什么不把产品作为买方与客体的关系呢

因此，您可以在Buyer.php中定义产品：

function products()
{
    return $this->hasManyThrough('App\Download', 'App\Product', 'id', 'buyer_id', 'product_id', 'id');
}

在控制器中，您可以像这样调用它：

$buyer->with([
  'products.province:id,name',
  'products.city:id,name'
  ])
    ->whereHas('products', function($query){
       $query->where('deleted', 0)
      })
    ->get()

---

然后您可以使用

returnresponse（）->json（['data'=>$buyer->products]，200）
请您显示这些表的定义/迁移。@Rwd我添加了表视图，希望它能让这个问题变得清晰谢谢，回答得真棒。它返回的权利，事情，只是一个小问题，我可以包括卖方数据在这个结果？