在laravel中获取php对象所需的键

我有一个选择信息，看起来像：

use Illuminate\Support\Facades\DB;
$arrays = DB::table('users')->where('id', Session::get('user_id'))->get();

当我回显

$arrays

时，会得到如下结果：

[{"id":2,"first_name":"Mukesh","last_name":"Aryal","birth_date":"2002-08-23","email":"aryalmukesh60m@gmail.com","password":"4cb22531c6a79ae334e9e9ca95575394","profession":"Student","gender":"male","age":15,"bio":"maaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa","preferred_people":"Anyone eXPLORE! Would Prefer","profile_picture":"me.jpg","full_name":"Mukesh Aryal","joined_date":"2018-04-29","user_json":"'{\"first_name\":\"Mukesh\",\"last_name\":\"Aryal\",\"birth_date\":\"2002-8-23\",\"birth_date_in_string\":\"23 August 2002\",\"email_address\":\"aryalmukesh60m@gmail.com\",\"password\":\"4cb22531c6a79ae334e9e9ca95575394\",\"profession\":\"Student\",\"gender\":\"male\",\"age\":\"15\",\"bio\":\"maaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\",\"profile_picture\":\"me.jpg\",\"full_name\":\"Mukesh Aryal\",\"joined_date\":\"2018-04-29\",\"joined_date_in_string\":\"29 April 2018\",\"friends\":[],\"posts\":[],\"address\":\"\",\"searches\":[],\"nickname\":\"\",\"likedSubjects\":[],\"facebookProfile\":{},\"twitterProfile\":{}}'"}]

---

现在，如何从整个对象中只回显

名字

$user = DB::table('users')->where('id', Session::get('user_id'))->first();

这将生成一个易于访问的单行/对象：

$user->first_name

$arrays->first\u name
将解决您的问题。并使用
first（）
而不是
get（）
我得到一个错误，它说：这个集合实例上不存在属性[first\u name]。就是这样！！！非常感谢。我会选择这是接受的答案时，该网站显示的时间。（目前10分钟后！）再次感谢！！！作者得到的JSON数组是因为Laravel将数组响应转换为JSON；）
<?php

$data='[{"id":2,"first_name":"Mukesh","last_name":"Aryal","birth_date":"2002-08-23","email":"aryalmukesh60m@gmail.com","password":"4cb22531c6a79ae334e9e9ca95575394","profession":"Student","gender":"male","age":15,"bio":"maaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa","preferred_people":"Anyone eXPLORE! Would Prefer","profile_picture":"me.jpg","full_name":"Mukesh Aryal","joined_date":"2018-04-29","user_json":"\'{\"first_name\":\"Mukesh\",\"last_name\":\"Aryal\",\"birth_date\":\"2002-8-23\",\"birth_date_in_string\":\"23 August 2002\",\"email_address\":\"aryalmukesh60m@gmail.com\",\"password\":\"4cb22531c6a79ae334e9e9ca95575394\",\"profession\":\"Student\",\"gender\":\"male\",\"age\":\"15\",\"bio\":\"maaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\",\"profile_picture\":\"me.jpg\",\"full_name\":\"Mukesh Aryal\",\"joined_date\":\"2018-04-29\",\"joined_date_in_string\":\"29 April 2018\",\"friends\":[],\"posts\":[],\"address\":\"\",\"searches\":[],\"nickname\":\"\",\"likedSubjects\":[],\"facebookProfile\":{},\"twitterProfile\":{}}\'"}]';

$data=json_decode($data,true);
echo $data[0]['first_name'];

$data=json_decode($data,true);

foreach($data as $row){
    echo $row['first_name'];
}