Php 将数组分解为多维数组（父级->；子级->；子级）

我有一个数组（$categories\u final），看起来像这样：

Array
(
    [0] => Accessories/Apron
    [1] => Accessories/Banners
    [2] => Accessories/Belts
    [3] => Brand/Brand1
    [4] => Brand/Brand2
    [5] => Apparel/Men/Belts
    [6] => Apparel/Men/Socks
    [7] => Apparel/Women/Leggings
)

我试图让它看起来像这样，这样我就可以将它添加到数据库中，作为我商店的类别结构：

Array
(
    [Accessories] => Array
        (
            [0] => Apron
            [1] => Banners
            [2] => Belts
        )
    [Apparel] => Array
        (
            [0] => Men => Array
                (
                    [0] => Belts
                    [1] => Socks
                )
            [1] => Women => Array
                (
                    [0] => Leggings
                )
        )

        ...etc

以下是我到目前为止得到的信息，但我无法确定如何将孩子添加到Men/&Women/：

$categories = array();
foreach ($categories_final as $cat) {
    $levels = explode('/', $cat);
    if (isset($categories[$levels[0]])) {
        if (!in_array($levels[1], $categories[$levels[0]])) {
            $categories[$levels[0]][]= $levels[1];
        }
    }
    else {
        $categories[$levels[0]][]= $levels[1];
    }
}
print_r($categories);

再一次，我被困在如何在他们各自的父母身上添加/腰带/袜子和/绑腿上

---

感谢您的帮助，谢谢

因为可以有无限数量的分支，所以您可能应该有一个递归解决方案。我尽了最大努力，得到了以下代码：

$arr = ['Accessories/Apron', 'Accessories/Banners', 'Accessories/Belts','Brand/Brand1','Brand/Brand2',
        'Apparel/Men/Belts', 'Apparel/Men/Socks', 'Apparel/Women/Leggings'];

$final = [];
foreach ($arr as $branch) {
    $temp = branchRecursive($branch);
    $final = array_merge_recursive($final, $temp);
}



function branchRecursive($branch) {
    // explode only first
    $newBranch = explode('/', $branch, 2);

    // A leaf, no more branches
    if(count($newBranch) != 2) {

        return $newBranch[0];
    }

    $array [ $newBranch[0] ]= branchRecursive($newBranch[1]);
    return $array;

}

它返回以下内容：

Array
(
    [Accessories] => Array
        (
            [0] => Apron
            [1] => Banners
            [2] => Belts
        )

    [Brand] => Array
        (
            [0] => Brand1
            [1] => Brand2
        )

    [Apparel] => Array
        (
            [Men] => Array
                (
                    [0] => Belts
                    [1] => Socks
                )

            [Women] => Leggings
        )

)

与代码唯一不同的是

[Women] => Leggings

而不是

[0] => Leggings

但我想睡觉，我的脑袋不工作，所以如果有人能指出该做什么改变，我会很感激。我希望这不是什么大问题：）

一种方法是将数组项“转换”为json，然后解码为数组

我首先做了一个中间步骤，其中字符串变成无效的json，但是preg_replace将内部的

{}

转换为

[]

使其有效。
然后与结果合并

$result =[];
foreach($arr as $val){
    $count = count(explode("/", $val));
    $str = '{"' . str_replace('/', '":{"', $val) . '"}' . str_repeat("}", $count-1);
    $json = preg_replace("/(.*)(\{)(.*?)(\})/", "$1[$3]", $str);
    $result = array_merge_recursive($result, json_decode($json, true));
}

Print_r($result);

---

此代码使您能够创建任意数量的分支

$source = array('Accessories/Apron ' ,
        'Accessories/Banners',
        'Accessories/Belts',
        'Brand/Brand1',
        'Brand/Brand2',
        'Apparel/Men/Belts',
        'Apparel/Men/Socks',
        'Apparel/Women/Leggings'
    );

function convert($categories_final) {
    $categories = array();
    foreach ($categories_final as $cat) {
        $levels = explode('/', $cat);
        // get category
        $category_name = $levels[0];
        array_shift($levels);
        if(!array_key_exists($category_name,$categories)) {
            $categories[$category_name] = array();
        }
        $tmp = &$categories[$category_name] ;
        foreach($levels as $index => $val){
            if($index + 1 === count($levels) ){
                $tmp[] = $val; 
            } else {
                $i = find_index($tmp , $val);
                if( $i == count($tmp) ) { // object not found , we create a new sub array
                    $tmp[] = array($val => array());
                }
                $tmp = &$tmp[$i][$val];
            }
        }

    }
    return $categories;
}

function find_index($array , $key) {
    foreach($array as $i => $val ) {
        if(is_array($val) && array_key_exists($key , $val) ){
            return $i ;
        }
    }
    return count($array);
}

print_r(convert($source));

这就是结果

Array
(
    [Accessories] => Array
        (
            [0] => Apron 
            [1] => Banners
            [2] => Belts
        )
    [Brand] => Array
        (
            [0] => Brand1
            [1] => Brand2
        )

    [Apparel] => Array
        (
            [0] => Array
                (
                    [Men] => Array
                        (
                            [0] => Belts
                            [1] => Socks
                        )
                )
            [1] => Array
                (
                    [Women] => Array
                        (
                            [0] => Leggings
                        )
                )
        )

)

---

这很有趣，节省了很多空间…我选择了另一个答案，因为它更符合我的风格，但你的解决方案是我要玩的东西！非常感谢。哈这就是为什么我要问你们：）…非常感谢你们的解决方案，这正是我想要的（结合上面的一个）-再次感谢@很乐意帮忙；）谢谢你提出的有趣的高质量问题。在这里变得非常罕见；D