Php 如何在sql中使用组concat连接三个表

我试图用组concat连接三个表。问题是主表的连接列是json格式的

查询正在工作，但一次又一次地重复连接列数据 查询->

表格->

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在GROUP\u CONCAT函数中使用DISTINCT关键字

即：

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在GROUP_CONCAT函数中使用DISTINCT关键字

即：

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在组连接时，执行

Distinct

检查

[SELECT tour_package.description AS description, tour_package.NAME AS NAME, GROUP_CONCAT( DISTINCT(destination_continent.NAME) ) AS continent_name, GROUP_CONCAT( DISTINCT(travel_style.NAME) ) AS travel_style_name, tour_package.id AS id, tour_package.img_path_thumb AS img_path_thumb, tour_package.continent_id, tour_package.travel_style_id FROM tour_package LEFT JOIN destination_continent ON FIND_IN_SET( destination_continent.id, REPLACE( REPLACE( REPLACE( tour_package.continent_id,  '\[',  '' ) ,  '\]',  '' ) ,  '\"',  '' ) )  LEFT JOIN travel_style ON FIND_IN_SET( travel_style.id, REPLACE( REPLACE( REPLACE( tour_package.travel_style_id,  '\[',  '' ) ,  '\]',  '' ) ,  '\"',  '' ) )  WHERE  `tour_package`.`DELETE` =0 &&  `destination_continent`.`DELETE` =0 LIMIT 0 , 30][1]

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在组连接时，执行

Distinct

检查

[SELECT tour_package.description AS description, tour_package.NAME AS NAME, GROUP_CONCAT( DISTINCT(destination_continent.NAME) ) AS continent_name, GROUP_CONCAT( DISTINCT(travel_style.NAME) ) AS travel_style_name, tour_package.id AS id, tour_package.img_path_thumb AS img_path_thumb, tour_package.continent_id, tour_package.travel_style_id FROM tour_package LEFT JOIN destination_continent ON FIND_IN_SET( destination_continent.id, REPLACE( REPLACE( REPLACE( tour_package.continent_id,  '\[',  '' ) ,  '\]',  '' ) ,  '\"',  '' ) )  LEFT JOIN travel_style ON FIND_IN_SET( travel_style.id, REPLACE( REPLACE( REPLACE( tour_package.travel_style_id,  '\[',  '' ) ,  '\]',  '' ) ,  '\"',  '' ) )  WHERE  `tour_package`.`DELETE` =0 &&  `destination_continent`.`DELETE` =0 LIMIT 0 , 30][1]

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thnx，现在我在自我解嘲，我必须吃一片补品来记忆thnx，现在我在自我解嘲，我必须吃一片补品来记忆

[SELECT tour_package.description AS description, tour_package.NAME AS NAME, GROUP_CONCAT( DISTINCT(destination_continent.NAME) ) AS continent_name, GROUP_CONCAT( DISTINCT(travel_style.NAME) ) AS travel_style_name, tour_package.id AS id, tour_package.img_path_thumb AS img_path_thumb, tour_package.continent_id, tour_package.travel_style_id FROM tour_package LEFT JOIN destination_continent ON FIND_IN_SET( destination_continent.id, REPLACE( REPLACE( REPLACE( tour_package.continent_id,  '\[',  '' ) ,  '\]',  '' ) ,  '\"',  '' ) )  LEFT JOIN travel_style ON FIND_IN_SET( travel_style.id, REPLACE( REPLACE( REPLACE( tour_package.travel_style_id,  '\[',  '' ) ,  '\]',  '' ) ,  '\"',  '' ) )  WHERE  `tour_package`.`DELETE` =0 &&  `destination_continent`.`DELETE` =0 LIMIT 0 , 30][1]