Php 根据尺寸制作包装

我正试图根据数据库中的信息创建数据包

数据库的组织方式如下：

ID ORDERID DIMENSION QUANTITY 
1    21    8400       25
2    21    7200       8
3    21    4300       5
4    21    3800       7

// assuming you have collected the results from your sql query like this:
while($r = $q->tech()) $dat[]=array($r['DIMENSION'],$r['QUANTITY']);

// you will end up with an array $dat: (dimension, quantity) like this:
// $dat=array(array(8400,25),array(7200,8),array(4300,5),array(3800,7));
// package size:
$n=10;

$cnt=0;                        // initialize package counter
$pack=array();                 // set up first package
$d=array_shift($dat);          // get first lot $d from $dat

do {     
  if ($d[1]>0){    
    $take=min($d[1],$n-$cnt);  // decide how much to take out ...
    $cnt+=$take;               // increase package counter
    $d[1]-=$take;$pack[]=array($d[0],$take); // tranfer the goods ...
                               // if package is full, start next one
    if ($cnt==$n) {$packs[]=$pack; $pack=array(); $cnt=0;}
  } else if(count($dat)>0){    // still elements in $dat left?
    $d=array_shift($dat);      // get the next lot $d from $dat
  } else break;    
} while(true);
if ($cnt>0) $packs[]=$pack;    // collect the last "stranded" package ...

echo str_replace("]],","]],\n ",json_encode($packs));    // as JSON string
// print_r($packs);            // conventional (bulky) PHP object notation

首先，从数据库获取信息

$sql = "SELECT ID, ORDERID, DIMENSION, QUANTITY FROM dimension WHERE ORDERID = 21 ORDER BY DIMENSION DESC";

$q = $conn => query($sql);

while($r = $q->tech()){
  $dim  =$r['DIMENSION '];
  $quant  =$r['QUANTITY '];
}

然后我从另一个表中检索数据，例如，我得到数字10

$query = "SELECT QUANTITY FROM panel WHERE ID = 21; 

$q = $conn->query($query);

while ($r=$q->fetch()){
  $number = 10;
}

从最长尺寸进行包装是非常重要的

例如，我有尺寸8400数量25。面板的最大数量是10，这意味着每10个面板将有两个数据包，剩余5个。 5转到下一个维度，我们将该面板的最大数量设置为$number。该维度的剩余部分进入下一维度，并保持不变

一旦我得到了包装所需的所有信息，最后包装解决方案应该是

-------------------
8400 x 10 - Packet1
-------------------
8400 x 10 - Packet2
-------------------
8400 x 5
7200 x 5 - Packet3
-------------------
7200 x 3
4300 x 5
3800 x 2 - Packet4
-------------------
3800 x 5 - Packet 5
-------------------

一旦我得到这些数据，我应该将其插入数据库 其中8400为尺寸，10，面板，“包装1”-名称

---

我被卡住了，不知道该怎么做。我不知道这个算法是否存在

您可以这样做：

ID ORDERID DIMENSION QUANTITY 
1    21    8400       25
2    21    7200       8
3    21    4300       5
4    21    3800       7

// assuming you have collected the results from your sql query like this:
while($r = $q->tech()) $dat[]=array($r['DIMENSION'],$r['QUANTITY']);

// you will end up with an array $dat: (dimension, quantity) like this:
// $dat=array(array(8400,25),array(7200,8),array(4300,5),array(3800,7));
// package size:
$n=10;

$cnt=0;                        // initialize package counter
$pack=array();                 // set up first package
$d=array_shift($dat);          // get first lot $d from $dat

do {     
  if ($d[1]>0){    
    $take=min($d[1],$n-$cnt);  // decide how much to take out ...
    $cnt+=$take;               // increase package counter
    $d[1]-=$take;$pack[]=array($d[0],$take); // tranfer the goods ...
                               // if package is full, start next one
    if ($cnt==$n) {$packs[]=$pack; $pack=array(); $cnt=0;}
  } else if(count($dat)>0){    // still elements in $dat left?
    $d=array_shift($dat);      // get the next lot $d from $dat
  } else break;    
} while(true);
if ($cnt>0) $packs[]=$pack;    // collect the last "stranded" package ...

echo str_replace("]],","]],\n ",json_encode($packs));    // as JSON string
// print_r($packs);            // conventional (bulky) PHP object notation

这将导致以下结果（JSON表示法）：

---

你可以这样做：

ID ORDERID DIMENSION QUANTITY 
1    21    8400       25
2    21    7200       8
3    21    4300       5
4    21    3800       7

// assuming you have collected the results from your sql query like this:
while($r = $q->tech()) $dat[]=array($r['DIMENSION'],$r['QUANTITY']);

// you will end up with an array $dat: (dimension, quantity) like this:
// $dat=array(array(8400,25),array(7200,8),array(4300,5),array(3800,7));
// package size:
$n=10;

$cnt=0;                        // initialize package counter
$pack=array();                 // set up first package
$d=array_shift($dat);          // get first lot $d from $dat

do {     
  if ($d[1]>0){    
    $take=min($d[1],$n-$cnt);  // decide how much to take out ...
    $cnt+=$take;               // increase package counter
    $d[1]-=$take;$pack[]=array($d[0],$take); // tranfer the goods ...
                               // if package is full, start next one
    if ($cnt==$n) {$packs[]=$pack; $pack=array(); $cnt=0;}
  } else if(count($dat)>0){    // still elements in $dat left?
    $d=array_shift($dat);      // get the next lot $d from $dat
  } else break;    
} while(true);
if ($cnt>0) $packs[]=$pack;    // collect the last "stranded" package ...

echo str_replace("]],","]],\n ",json_encode($packs));    // as JSON string
// print_r($packs);            // conventional (bulky) PHP object notation

这将导致以下结果（JSON表示法）：

---

这正是我想要的。一旦我得到这些信息，我需要将其存储在数据库中。我的表格是有组织的ID | ORDERID | DIMENSION | QUANTITY | NAME。我有订单id、尺寸（8400）和数量10。对于第一套，订单名称可以是Packet1，对于第二套Packet2，对于第三种情况，两套的Packet3将是相同的名称8400和7200。它增加1。Idk，如果可能的话。谢谢，这正是我想要的。一旦我得到这些信息，我需要将其存储在数据库中。我的表格是有组织的ID | ORDERID | DIMENSION | QUANTITY | NAME。我有订单id、尺寸（8400）和数量10。对于第一套，订单名称可以是Packet1，对于第二套Packet2，对于第三种情况，两套的Packet3将是相同的名称8400和7200。它增加1。Idk，如果可能的话。非常感谢。