Php 插入到不填充数据库表中

我有一个检查SubmitName表的脚本，如果approve1和Approve2都不是空的，它会将数据插入clanstats。没有mysql_错误，它只是重定向到头，而没有在clanstats表中插入任何内容，所以我不知道发生了什么。下面是代码

<?php
include("user.php");
$id = $_GET['id'];
$result = mysql_query("SELECT * FROM submitgame WHERE id='$id'") or die(mysql_error());
$playerclan = $row['playerclan'];
$opponentclan = $row['opponentclan'];
$win = $row['win'];
$approve1 = $row['approve1'];
$approve2 = $row['approve2'];
if($win == "won") { 
    $win = 1;
    $points = 2;
    $win2 = 0;
    $points2 = 1;
}
else {
    $win = 0;
    $points = 1;
    $win2 = 1;
    $points2 = 2;
}
if($approve1 != "" && $approve2 != "") { 
    $query=mysql_query("INSERT INTO clanstats (clan, points, wins) VALUES ('$playerclan', '$points', '$win')");
    $query=mysql_query("INSERT INTO clanstats (clan, points, wins) VALUES ('$opponentclan', '$points2', '$win2')");
    echo mysql_error($query);
}
else {
    header("location:../approvegames.php");
}
mysql_close($con);
header("location:../approvegames.php");
?>

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我想你漏了一行。也许是这样的：

$row = mysql_fetch_row($result)

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@Alex您需要选择代码并单击文本区域上方的{}图标以显示代码。基本上，它只需在每行前面添加四个空格，就可以正确地显示为代码。您确定执行了两个insert查询吗？我的意思是，如果$approve1或$approve2变量与空字符串不同，您是否尝试过使用var_转储$approve1和$approve2的值？另外，始终使用exit/die after header'Location:…'语句，以避免进一步执行代码时出现意外结果。请稍候。。您的$结果如何变成$行？。。你不应该在中间有MySqLyFuffChyAsSOC吗？在这一切之上，如果我决定手动更改URL为……ID=’，你就被拧了。将表格提交给我；-即

    <?php
    //first off are you connecting, ill presume so
    include("user.php");
    //sql injection!!!
    $id = mysql_real_escape_string($_GET['id']);
    $result = mysql_query("SELECT * FROM submitgame WHERE id='$id' limit 1") or die(mysql_error());
    //you were missing this
    $row=mysql_fetch_array($result);
    $playerclan = $row['playerclan'];
    $opponentclan = $row['opponentclan'];
    $win = $row['win'];
    $approve1 = $row['approve1'];
    $approve2 = $row['approve2'];

    if($win == "won") { 
        $win = 1;
        $points = 2;
        $win2 = 0;
        $points2 = 1;
    }else{
        $win = 0;
        $points = 1;
        $win2 = 1;
        $points2 = 2;
    }

    if($approve1 != "" && $approve2 != "") { 
        //you can have multiple inserts
        $query=mysql_query("INSERT INTO clanstats (clan, points, wins) VALUES 
        ('$playerclan', '$points', '$win'),
        ('$opponentclan', '$points2', '$win2')");
        header("location:../approvegames.php");
        //adding die after the header will make sure nothing else gets executed
        die();
    }else{
        header("location:../approvegames.php");
        die();
    }
   //no need to kill the connection as it will close when the script exits
    ?>