Php 如何在Laravel的Eloquent中设置mysql位数据类型？（拉威尔5.4）

我只有一个操作来停用用户的资源。该操作使用一个位值来激活/停用资源，但我很惊讶我无法按预期设置位值。该值始终设置为1，即创建资源时的默认值

   public function deactivate(Request $request)

        {

           $resourceId= $request->get('resourceId');

           $resource= \App\Resource::find($resourceId);

           //I've tried the two statements below separetely

           $resource->active= false; //didn't work

           $resource->active= 0;   //didn't work

            //I performed the test below with another column and it worked
            //so the problem isn't my model.

            $resource->anotherProperty = 10;



            $resource->save();
     }

尽管我不认为问题出在我的模型上，但我使用的是数据库优先的方法，问题可能出在我创建的模型上

class Resource extends Model
 {



 protected $table = 'resource';
  protected $primaryKey = 'resource_id';

protected $fillable = array( 'announcer_id', 'announcer_type', 'data',  'active');

   public $timestamps = false;
   protected $connection = 'custom_connection';
}

几分钟后更新

CREATE TABLE `resource` (
 `resource_id` int(10) unsigned NOT NULL AUTO_INCREMENT,
 `announcer_id` int(10) unsigned NOT NULL,
 `announcer_type` tinyint(3) unsigned NOT NULL,
 `data` date DEFAULT NULL,
 `active` bit(1) DEFAULT b'1',
  PRIMARY KEY (`resource_id`)
 ) ENGINE=InnoDB AUTO_INCREMENT=583 DEFAULT CHARSET=latin1;

---

经过研究，我发现MySQL有一个布尔数据类型，存储为tinyint1

我改变了我的桌子

alter table resource modify column active boolean  not null;

现在在我的控制器上

$resource->active= false; //works

---

显示表架构