Php 在simplexml\u load\u文件中获取XML节点名而不复制

我使用以下代码获取XML的节点名称：

$url = 'https://www.toptanperpa.com/xml.php?c=shopphp&xmlc=e7ef2a0122';
$xml = simplexml_load_file($url) or die("URL Read Error");

echo $xml->getName() . "<br>";
    
    foreach ($xml->children() as $child) {
        echo $child->getName() . "<br>";
        
        foreach ($child->children() as $child2) {
            echo $child2->getName() . "<br>";
            
            foreach ($child2->children() as $child3) {
                echo $child3->getName() . "<br>";
                
                foreach ($child3->children() as $child4) {
                echo $child4->getName() . "<br>";
                }
            }
        }
    }

我应该使用

array\u unique

还是有更好的方法

---

谢谢

我使用了递归函数这很简单

function getChildrens($x) {
  $children = array();
  array_push($children, $x->getName());
  foreach ($x->children() as $chld) {
    $children = array_merge($children, getChildrens($chld));
  }
  return array_unique($children);
}
echo implode("<br>", getChildrens($xml));

函数getChildrens（$x）{ $children=array（）； 数组_push（$children，$x->getName（））； foreach（$x->children（）作为$chld）{ $children=array_merge（$children，getChildrens（$chld））； } 返回数组_unique（$children）； } echo内爆（“
”，getChildrens（$xml））；

---

getChildrens

返回元素的唯一名称数组

function getChildrens($x) {
  $children = array();
  array_push($children, $x->getName());
  foreach ($x->children() as $chld) {
    $children = array_merge($children, getChildrens($chld));
  }
  return array_unique($children);
}
echo implode("<br>", getChildrens($xml));