Php Symfony密码重置,无FOS捆绑包

Php Symfony密码重置,无FOS捆绑包,php,symfony,Php,Symfony,我正在尝试制作一个用户可以轻松更改密码的表单。我希望我的逻辑是正确的,但是我得到一个错误如下 Expected argument of type "string", "AppBundle\Form\ChangePasswordType" given 这是我的控制器 public function changePasswdAction(Request $request) { $changePasswordModel = new ChangePassword(); $form =

我正在尝试制作一个用户可以轻松更改密码的表单。我希望我的逻辑是正确的,但是我得到一个错误如下

Expected argument of type "string", "AppBundle\Form\ChangePasswordType" given
这是我的控制器

public function changePasswdAction(Request $request)
{
    $changePasswordModel = new ChangePassword();
    $form = $this->createForm(new ChangePasswordType(), $changePasswordModel);

    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        // perform some action,
        // such as encoding with MessageDigestPasswordEncoder and persist
        return $this->redirect($this->generateUrl('homepage'));
    }

    return $this->render(':security:changepassword.html.twig', array(
        'form' => $form->createView(),
    ));
}
这是我的模型

class ChangePassword
{

/**
 * @SecurityAssert\UserPassword(
 *     message = "Wrong value for your current password"
 * )
 */
protected $oldPassword;

/**
 * @Assert\Length(
 *     min = 6,
 *     minMessage = "Password should by at least 6 chars long"
 * )
 */
protected $newPassword;

/**
 * @return mixed
 */
public function getOldPassword()
{
    return $this->oldPassword;
}

/**
 * @param mixed $oldPassword
 */
public function setOldPassword($oldPassword)
{
    $this->oldPassword = $oldPassword;
}

/**
 * @return mixed
 */
public function getNewPassword()
{
    return $this->newPassword;
}

/**
 * @param mixed $newPassword
 */
public function setNewPassword($newPassword)
{
    $this->newPassword = $newPassword;
}   
}

这是我的更改密码类型

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;

class ChangePasswordType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('oldPassword', 'password');
        $builder->add('newPassword', 'repeated', array(
            'type' => 'password',
            'invalid_message' => 'The password fields must match.',
            'required' => true,
            'first_options'  => array('label' => 'Password'),
            'second_options' => array('label' => 'Repeat Password'),
        ));
    }

}
这是我的观众

{{ form_widget(form.current_password) }}
{{ form_widget(form.plainPassword.first) }}
{{ form_widget(form.plainPassword.second) }}
@dragoste提到的解决方案对我很有效。 我改了下面一行

$form = $this->createForm(new ChangePasswordType(), $changePasswordModel);
用这条线,

$form = $this->createForm(ChangePasswordType::class, $changePasswordModel);

在最近的Symfony版本中,您只能在
createForm

改变

$form = $this->createForm(new ChangePasswordType(), $changePasswordModel);



问题在于
$this->createForm(新的ChangePasswordType(),$changePasswordModel)createForm需要一个字符串作为第一个参数。根据bundle
'your\bundle\Form\ChangePasswordType'
将完全限定的类名作为字符串提供。实际上,执行
ChangePasswordType::class
总比手动输入类名好。重构代码时没有什么意外;-)@德拉戈斯特这是非常好的工作!我正在更新这个问题。
$form = $this->createForm(ChangePasswordType::class, $changePasswordModel);