如何从数据库中刷新1个值而不刷新PHP文件中的网页
您可以使用Ajax编写函数,并在一段时间后调用它,然后将Ajax请求发送到您的tes.php文件,计算您的数据并在页面中显示您想要的响应:我给您举个Ajax示例如何从数据库中刷新1个值而不刷新PHP文件中的网页,php,mysql,Php,Mysql,您可以使用Ajax编写函数,并在一段时间后调用它,然后将Ajax请求发送到您的tes.php文件,计算您的数据并在页面中显示您想要的响应:我给您举个Ajax示例 <?php session_start(); $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'kumkum09'; $dbname = 'eoffice_db'; $conn = new mysqli($dbhost, $
<?php
session_start();
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'kumkum09';
$dbname = 'eoffice_db';
$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
if(! $conn )
{
die('Could not connect: ' . mysqli_error());
}
if (isset($_SESSION['user']) == '') {
// Fungsi Validasi Login dan Create session
if(isset($_POST['user'])){
$username = mysqli_real_escape_string($conn, $_POST['user']);
$password = mysqli_real_escape_string($conn, $_POST['pass']);
$query = mysqli_query($conn, "SELECT * FROM users WHERE password=md5('$password') and username='$username'");
$row = mysqli_fetch_array($query);
$num_row = mysqli_num_rows($query);
if ($num_row > 0)
{
$_SESSION['user']=$row['username'];
$user=$_SESSION['user'];
// echo "User: ".$user."<br>";
// Fungsi Cek Token dan Create Token
$cektoken = "SELECT * FROM users WHERE username='$user'";
$resultcekuser = $conn->query($cektoken);
$rowtoken = $resultcekuser->fetch_object();
$tokennye = $rowtoken->token;
if($tokennye==""){
$tokenz = md5($user.time().rand());
$updttokenuser = "UPDATE users SET token='$tokenz' WHERE username='$user'";
$prosesupdttokenuser = $conn->query($updttokenuser);
}
$createsessiontoken = mysqli_query($conn, "SELECT * FROM users WHERE username='$user'");
$sessiontoken = mysqli_fetch_array($createsessiontoken);
$_SESSION['token'] = $sessiontoken['token'];
header("location: tes.php");
}
}
else
{
// header("location: index.php");
}
}
else
{
$user = $_SESSION['user'];
$token = $_SESSION['token'];
// Counting Jumlah Notifikasi Memo Belum Baca
$notifmemo = "SELECT * FROM memo WHERE username_tujuan='$user' and status='Belum Dibaca'";
$resultnotifmemo = $conn->query($notifmemo);
$rowcount=mysqli_num_rows($resultnotifmemo);
}
?>
在test.php页面中,对记录进行计数,然后仅回显或返回它您应该使用ajax。这就是ajax请求出现的地方,您必须使用Javascript。有关ajax的更多信息,请阅读。太棒了。服务器端帮不上忙耶。。。!AJAX将帮助您尝试使用AJAX。
$(function(){
setTimeout(notification,30000);
function notification(){
$.ajax({
data : 'get',
dataType : 'html',
url : 'test.php'
data : {check_data : 1},
success : function(data){
$('#id of your div').html(data);
},
error : function(){
console.log('Error');
}
});
}
});