Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/php/231.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
PHP MySQL云登录表单_Php_Mysql_Sql_Forms_Login - Fatal编程技术网

PHP MySQL云登录表单

PHP MySQL云登录表单,php,mysql,sql,forms,login,Php,Mysql,Sql,Forms,Login,我有一个GoogleAppEngine应用程序(php网站),它连接了一个云SQL实例数据库。首先,我的app.yaml是: application: applicationid version: 1 runtime: php api_version: 1 handlers: - url: /(.*\.(gif|png|jpg|ico|js|css)) static_files: \1 upload: (.*\.(gif|png|jpg|ico|js|css)) - url: /dbc

我有一个GoogleAppEngine应用程序(php网站),它连接了一个云SQL实例数据库。首先,我的app.yaml是:

application: applicationid
version: 1
runtime: php
api_version: 1

handlers:
- url: /(.*\.(gif|png|jpg|ico|js|css))
 static_files: \1
 upload: (.*\.(gif|png|jpg|ico|js|css))

 - url: /dbconn.php
 script: dbconn.php

 - url: /logincheck.php
 script: logincheck.php

 - url: /loginsuccess.php
 script: loginsuccess.php

 - url: /register.php
 script: register.php

 - url: /sign.php
  script: sign.php

  - url: /viewcurrent.php
  script: viewcurrent.php  

 - url: /.*
  script: mainpage.php
我在主页上有以下登录表单:

  <form method="post" enctype="application/x-www-form-urlencoded" action="logincheck.php" autocomplete="off" >
   <table>
    <tr>
    <td><label for="username">Username</label></td>
    <td><input type="text" name="username"></input></td>
    </tr>
    <tr>
    <td><label for="password">Password</label></td>
     <td><input name="password" type="password"></input></td>
     </tr>
     <tr>
     <td><input type="submit" value="Submit"</td>

用户名
暗语
因此,假设用户登录后被发送到“loginsucess.php”。我在CloudSQL上设置了正确的数据库,并带有正确的字段,如用户名和密码。但是,当用户键入正确的用户名和密码时,页面只需重新加载完全相同的url即可:

而不是在“logincheck.php”中实际执行操作


你知道我做错了什么吗?

请在数据库交互中添加一些错误检查,并在打开
后立即在文件顶部添加错误报告。你有没有收到任何错误?我刚刚重新排列了app.yaml文件,现在在logincheck.php中出现以下错误(显示的代码是整个文件,没有其他内容):警告:session_start():无法发送会话缓存限制器-第3行已发送标头警告:无法修改标头信息-第20行已发送标头在任何输出发生之前,必须启动会话。是否添加了其余的错误检查?我已设法修复第一个错误。但第二个错误仍然存在。由于标头,但我填写并发送表单后,需要将用户发送到正确的页面——
  <?php
  session_start();

 require "dbconn.php";

 $username = $_POST['username'];
 $password = $_POST['password'];

  $query = "SELECT * FROM students WHERE username = '".$username."' 
  AND password = '".$password."'";

 $result = $connect->query($query);

 $row = $result->fetch_assoc();

 if ($row != null)
 {
$_SESSION['username'] = $username;
header("Location: loginsuccess.php");

exit();
 }
 else
 {
 header("Location: wrongdetails.php?showerror=1");
 exit();
 }
 ?>