Php 如何将$data发送到fetchOne apigility rest？

如何将

$data

（some one values->array）发送到Rest Apigility进行查询并返回结果这是我发送

$data

的代码

$body = $this->getRequest()->getContent();
    $json = json_decode($body, true);
    $conditions =array(
            'artist'    =>  $json['data']
    );
    $client = new Client();

    $uri = "http://localhost:81/ApigilityNew/public/albums";

    $user        = 'admin';
    $password    = 'admin';

    //url del servicio REST
    $client->setUri($uri);
    //establecer metodo GET-POST
    $client->setMethod('GET');
    //tiempo de peticion
    $client->setOptions(
            [
                    'maxredirects'  => 0,
                    'timeout'       => 60
            ]
    );
    $client->setHeaders(['Accept' => 'application/json', 'Contet-Type' => 'application/json']);
    $client->setAuth($user, $password , $client::AUTH_BASIC);
    $client->setParameterGet($conditions);
    $response = $client->send($client->getRequest());

对于获取Apigility上的

$data

，此：

AlbumResource.php

   /**
     * Fetch a resource
     *
     * @param  array $condiciones
     * @return ApiProblem|mixed
     */
    public function fetch($conditions) //$id
    {
        //return new ApiProblem(405, 'The GET method has not been defined for individual resources');
        return $this->mapper->fetchOne($condiciones);
    }

  public function fetchOne($conditions) 
    {

        $sql = ' SELECT album.id, album.artist, album.title, pais.nombre_pais, biografia.genero, biografia.ocupacion, biografia.sitio_web
                 FROM album
                    LEFT JOIN pais ON  pais.id_album = album.id
                    LEFT JOIN biografia ON biografia.id_album = album.id
                WHERE 1 = 1 ';

        if (!empty($conditions['criterio_busqueda']))
        {
            $sql = $sql. " AND album.artist LIKE '%".$condiciones['criterio_busqueda']."%'";
        }

        $resultset = $this->adapter->query($sql, array($data));
        $data = $resultset->toArray();
        if (!$data) {
            return false;
        }
        return $data;
    }//end function

AlbumMapper.php

   /**
     * Fetch a resource
     *
     * @param  array $condiciones
     * @return ApiProblem|mixed
     */
    public function fetch($conditions) //$id
    {
        //return new ApiProblem(405, 'The GET method has not been defined for individual resources');
        return $this->mapper->fetchOne($condiciones);
    }

  public function fetchOne($conditions) 
    {

        $sql = ' SELECT album.id, album.artist, album.title, pais.nombre_pais, biografia.genero, biografia.ocupacion, biografia.sitio_web
                 FROM album
                    LEFT JOIN pais ON  pais.id_album = album.id
                    LEFT JOIN biografia ON biografia.id_album = album.id
                WHERE 1 = 1 ';

        if (!empty($conditions['criterio_busqueda']))
        {
            $sql = $sql. " AND album.artist LIKE '%".$condiciones['criterio_busqueda']."%'";
        }

        $resultset = $this->adapter->query($sql, array($data));
        $data = $resultset->toArray();
        if (!$data) {
            return false;
        }
        return $data;
    }//end function

---

怎样才能得到结果？现在它只从Apigility返回不支持的媒体类型

您的

ContentType

标题中有一个输入错误：

'Contet-Type' => 'application/json'

应该是：

'Content-Type' => 'application/json'

---

这可能就是为什么您会收到一条不受支持的媒体类型消息

我将此用作指南，但不起作用[link]@DiegoA。该应用程序应该可以正常工作。你能更具体地说明问题是什么吗。你收到错误信息了吗？什么信息？你什么时候在哪里买的？请添加准确消息的报价。。。