Php Laravel MethodNotAllowedHttpException无消息-尝试插入mysql表
我对Laravel很陌生,我现在使用的是5.7版。当我试图将一些表单数据放入mysql表时,我遇到了这个错误 Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException 没有消息 但是我不知道我出了什么问题。如果可以的话,请帮助我。请看下面我的代码 我的路线:Php Laravel MethodNotAllowedHttpException无消息-尝试插入mysql表,php,mysql,laravel-5.7,Php,Mysql,Laravel 5.7,我对Laravel很陌生,我现在使用的是5.7版。当我试图将一些表单数据放入mysql表时,我遇到了这个错误 Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException 没有消息 但是我不知道我出了什么问题。如果可以的话,请帮助我。请看下面我的代码 我的路线: Route::get('/invo_admin/create_new_offer', 'CreatenewofferController@index')->
Route::get('/invo_admin/create_new_offer', 'CreatenewofferController@index')->name('create_new_offer');
我还有一个名为admin的子文件夹,其中有我的仪表板视图
Route::resource('admin', 'CreatenewofferController');
我的模型:
namespace App;
use Illuminate\Database\Eloquent\Model;
class Offers extends Model
{
protected $fillable =[
'offer_name',
'offer_image',
'offer_discription',
'offer_vendor',
'offer_reward_amount',
'offer_limit',
'offer_duration',
'offer_status'
];
}
我的控制器:
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Offers;
class CreatenewofferController extends Controller
{
/**
* Create a new controller instance.
*
* @return void
*/
public function __construct()
{
$this->middleware('auth');
}
/**
* Display a listing of the resource.
*
* @return \Illuminate\Http\Response
*/
public function index()
{
$title = 'this is a title';
return view('admin.create_new_offer')->with('title',$title);
}
/**
* Show the form for creating a new resource.
*
* @return \Illuminate\Http\Response
*/
public function create()
{
return view('admin.create_new_offer');
}
/**
* Store a newly created resource in storage.
*
* @param \Illuminate\Http\Request $request
* @return \Illuminate\Http\Response
*/
public function store(Request $request)
{
$this->validate($request,[
'offer_name' => 'required',
'offer_image' => 'required',
'offer_discription' => 'required',
'offer_vendor' => 'required',
'offer_reward_amount' => 'required',
'offer_limit' => 'required',
'offer_duration' => 'required',
'offer_status' => 'required'
]);
$offers = new Offers([
'offer_name' => $request->get('offer_name'),
'offer_image' => $request->get('offer_image'),
'offer_discription' => $request->get('offer_discription'),
'offer_vendor' => $request->get('offer_vendor'),
'offer_reward_amount' => $request->get('offer_reward_amount'),
'offer_limit' => $request->get('offer_limit'),
'offer_duration' => $request->get('offer_duration'),
'offer_status' => $request->get('offer_status')
]);
$offers->save();
return redirect()->route('admin.create_new_offer')->with('success', 'You have successfully added a new offer');
}
}
我的看法是:
<form role="form" method="POST" action="{{ url('invo_admin/create_new_offer') }}">
{{csrf_field()}}
<!-- text input -->
<div class="form-group">
@if(count($errors) > 0)
<ul>
@foreach ($errors ->all as $error)
<li class="text-danger">{{error}}</li>
@endforeach
</ul>
@endif
@if(\Session::has('success'))
<p>{{\Session::get('success')}}</p>
@endif
<label>Name</label>
<input type="text" class="form-control" name="offer_name" placeholder="Offer Name">
</div>
</form>
将此添加到您的路线中
Route::post('/invo_admin/create_new_offer', 'CreatenewofferController@store')->name('create_new_offer');
它接受post请求并将其传递给控制器中的store方法。所以我处理了这个问题 我的路线混乱不堪;例如,永远不要使用GET或POST路由,始终使用追索权路由 不好
Route::get('admin/vendors', 'VendorController@index')->name('whatever_name');
Route::post('admin/vendors','VendorController@index')->name('whatever_name');
非常好:
Route::resource('admin/vendors', 'VendorController', ['as'=>'admin']);
正确路线的最后一部分。。。
['as'=>'admin']
我希望这能有所帮助。看起来您正在使用Route::get来处理post请求。你需要创建一个与你的store controller方法相对应的post路由。我试过了,但它不起作用,你介意给我一个代码示例,这样我就可以确保我做得正确吗?这已经停止了错误,但是仍然没有向数据库添加任何内容。是的。你下面的评论很好。我的目的是定义一个路由来接受post请求。 front facing website admin panel "admin.vendors.store"
public function create()
{
//
}
/**
* Store a newly created resource in storage.
*
* @param \Illuminate\Http\Request $request
* @return \Illuminate\Http\Response
*/
public function store(Request $request)
{
//
}