Php POST方法和数组

这是我的第一个php项目。我创建了一个网站，用户可以上传他们的图片，然后查看其他用户的图片，一次一个人（类似于旧的hotornot.com）。以下代码的工作原理如下：

我创建了一个数组（称为$alluser），其中包含除当前登录的用户（$user）之外的所有成员

我创建了一个数组（称为$usersiviewed），其中包含$user以前喜欢（存储在likeprofile表中）或不喜欢（存储在dislikeprofile表中）的所有成员。likeprofile和dislikeprofile的第一列包含喜欢/不喜欢的用户的名称，第二列包含他们喜欢/不喜欢的成员的名称

我使用数组_diff从$alluser中去掉$usersiviewed。这是$user可以查看的用户列表（即，他们过去不喜欢或不喜欢的人）。 现在的问题是，当我单击like按钮时，它会用数组中下一个人的名字更新likeprofile表（即，不是我当前正在查看的照片的人，而是下一个显示照片的人）。此外，如果我刷新当前页面，则出现在当前页面上的个人资料会自动被我“喜欢”。如果你能给我一些建议，我将不胜感激

<?php 

// viewprofiles.php
include_once("header.php");

echo $user.' is currently logged in<br><br>';

echo <<<_END
<form method="post" action="viewprofiles.php"><pre>
<input type="submit" name ="choice" value="LIKE" />
<input type="submit" name ="choice" value="NEXT PROFILE" />
</pre></form>
_END;


$allusers = array();

//Create the $allusers array, comprised of all users except me
$result = queryMysql("SELECT * FROM members");
$num = mysql_num_rows($result);
for ($j = 0 ; $j < $num ; ++$j)
{
$row = mysql_fetch_row($result);
if ($row[0] == $user) continue;
$allusers[$j] = $row[0];
}



//Create the $i_like_these_users array, comprised of all users i liked
$result = queryMysql("SELECT * FROM likeprofile WHERE user='$user'");
$num = mysql_num_rows($result);
for ($j = 0 ; $j < $num ; ++$j)
{
$row = mysql_fetch_row($result);
$i_like_these_users[$j] = $row[1];
}

//Create the $i_dislike_these_users array, comprised of all users i disliked
$result = queryMysql("SELECT * FROM dislikeprofile WHERE user='$user'");
$num = mysql_num_rows($result);
for ($j = 0 ; $j < $num ; ++$j)
{
$row = mysql_fetch_row($result);
$i_dislike_these_users[$j] = $row[1];
}

//Create the $usersiviewed array, comprised of all users i have either liked or disliked
if (is_array($i_like_these_users) && is_array($i_dislike_these_users))
{
$usersiviewed = array_merge($i_like_these_users,$i_dislike_these_users);
}
elseif(is_array($i_like_these_users))
{
$usersiviewed = $i_like_these_users;
}
else
{
$usersiviewed = $i_dislike_these_users;
}

// this removes from the array $allusers (i.e., profiles i can view) all $usersviewed (i.e., all the profiles i have already either liked/disliked)
if (is_array($usersiviewed))
{
$peopleicanview = array_diff($allusers, $usersiviewed);
$peopleicanview = array_values($peopleicanview); // this re-indexes the array
}
else {
$peopleicanview = $allusers;
$peopleicanview = array_values($peopleicanview); // this re-indexes the array
}


$current_user_profile = $peopleicanview[0];
echo 'check out '.$current_user_profile.'s picture <br />';
if (file_exists("$current_user_profile.jpg"))
{echo "<img src='$current_user_profile.jpg' align='left' />";}

// if i like or dislike this person, the likeprofile or dislikeprofile table is updated with my name and the name of the person who liked or disliked
if (isset($_POST['choice']) && $_POST['choice'] == 'LIKE')
{
$ilike = $current_user_profile;
$query = "INSERT INTO likeprofile VALUES" . "('$user', '$ilike')";
if (!queryMysql($query)) echo "INSERT failed: $query<br />" . mysql_error() . "<br /><br />";
}

if (isset($_POST['choice']) && $_POST['choice'] == 'NEXT PROFILE')
{
$idontlike = $current_user_profile;
$query = "INSERT INTO dislikeprofile VALUES" . "('$user', '$idontlike')";
if (!queryMysql($query)) echo "INSERT failed: $query<br />" . mysql_error() . "<br /><br />";
}

?> 

---

因为当您刷新页面时，它会发送
当你喜欢一个用户时，下一个用户会喜欢它。。在获取行时，您的for循环中有一些内容…而不是for循环在循环时尝试一次…我希望它将解决您的问题
您正在使用当前加载的用户计算
$iLike
变量，然后使用该用户更新数据库

您可能应该稍微更改一下应用程序逻辑：


除了like/not like变量外，还将您喜欢或不喜欢的用户的用户ID作为POST参数传递
将表单处理逻辑移到页面顶部（或者更好地将表单处理与HTML显示分开）

另外，最好不要在PHP中使用
mysql.*
扩展。使用
mysqli
或
PDO。

试着做两种不同的形式。一个用“喜欢”，另一个用“下一个”，以避免从同一形式喜欢

提交表单时，页面会刷新，因此在字符串
$current\u user\u profile=$peopleicanview[0]中
array
$peopleicanview
没有来自previuos页面的用户（提交前），您必须附加它，例如在隐藏字段中

"INSERT INTO likeprofile VALUES" . "('$user', '".$_POST['current_user']."')"

ps从表单中删除

让我们从简化和组织代码开始

谢谢！！这太完美了！
"INSERT INTO likeprofile VALUES" . "('$user', '".$_POST['current_user']."')"

<?php 
 // viewprofiles.php
include_once("header.php");

//if form is sent, process the vote.
//Do this first so that the user voted on wont be in results later(view same user again)
//use the user from hidden form field, see below
$userToVoteOn = isset($_POST['user-to-vote-on']) ? $_POST['user-to-vote-on'] : '';

    // if i like or dislike this person, the likeprofile or dislikeprofile table is updated with my name and the name of the person who liked or disliked
if (isset($_POST['like']))
{
    $query = "INSERT INTO likeprofile VALUES" . "('$user', '$userToVoteOn ')";
    if (!queryMysql($query)) 
        echo "INSERT failed: $query<br />" . mysql_error() . "<br /><br />";
}

if (isset($_POST['dislike']))
{
    $query = "INSERT INTO dislikeprofile VALUES" . "('$user', '$userToVoteOn ')";
    if (!queryMysql($query))
        echo "INSERT failed: $query<br />" . mysql_error() . "<br /><br />";
}

//now we can create array of available users.
$currentProfileUser = array();

//Create the $currentProfileUser array,contains data for next user.
//join the 2 other tables here to save php processing later.
$result = queryMysql("SELECT `user` FROM `members`
                      WHERE `user` NOT IN(SELECT * FROM `likeprofile` WHERE user='$user')
                      AND `user` NOT IN(SELECT * FROM `dislikeprofile` WHERE user='$user')
                      and `user` <> '$user'
                      LIMIT 1");
//no need for a counter or loop, you only need the first result.
if(mysql_num_rows > 0)
{
    $row = mysql_fetch_assoc($result);
    $current_user_profile = $row['user'];
}
else
 $current_user_profile = false;



echo $user.' is currently logged in<br><br>';  

//make sure you have a user
if($current_user_profile !== false): ?>
<form method="post" action="viewprofiles.php">
    <input type="hidden" name="user-to-vote-on" value="<?=$current_user_profile?>" />
    <input type="submit" name ="like" value="LIKE" />
</form>
<form method="post" action="viewprofiles.php">
    <input type="hidden" name="user-to-vote-on" value="<?=$current_user_profile?>" />
    <input type="submit" name ="dislike" value="NEXT PROFILE" />
</form>

check out <?=$current_user_profile?>'s picture <br />
    <?php    if (file_exists("$current_user_profile.jpg")): ?>
       <img src='<?=$current_user_profile.jpg?>' align='left' />
    <?php    endif; //end check if image exists ?>
<?php else: //no users found ?>
 Sorry, there are no new users to view
<?php endif; //end check if users exists. ?>