友谊查询-PHP&；mysql

下面是我返回会话用户朋友的查询

  $new_friends2 = $db->query("
  SELECT user.id, user.name_surname
  FROM user
  JOIN friendship ON user.id = friendship.sender_id or user.id = friendship.receiver_id
  WHERE (friendship.receiver_id !=" . $_SESSION["SES_USER_ID"] . " OR friendship.sender_id !=" . $_SESSION["SES_USER_ID"] . ")                  
  AND user.id != " . $_SESSION["SES_USER_ID"] . "");
  $new_friends2->setFetchMode(PDO::FETCH_ASSOC);
  $new_friends_data2 = $new_friends->fetchAll();
  //look carefully I change some equations from = to !=

WHERE (friendship.receiver_id !=" . $_SESSION["SES_USER_ID"] . " OR friendship.sender_id !=" . $_SESSION["SES_USER_ID"] . ")

$new\u friends=$db->query（“
选择user.id、user.name\u姓氏
来自用户
在user.id=friendy.sender\u id或user.id=friendy.receiver\u id上加入友谊
其中（Friendly.receiver_id=“.$”会话[“SES_用户_id”]”或Friendly.sender_id=“.$”会话[“SES_用户_id”]”）
和user.id！=“$”会话[“SES\u user\u id”]。”；
$new_friends->setFetchMode（PDO:：FETCH_ASSOC）；
$new\u friends\u data=$new\u friends->fetchAll（）；

它运行良好，没有任何问题。现在我想用新的属性来改进我的站点，所以我想在我的站点中添加“新人”部分。获取的用户不得会话用户的朋友及其本人

我试着在“你可能知道”部分使用下面的代码。但它再次返回会话用户的朋友

  $new_friends2 = $db->query("
  SELECT user.id, user.name_surname
  FROM user
  JOIN friendship ON user.id = friendship.sender_id or user.id = friendship.receiver_id
  WHERE (friendship.receiver_id !=" . $_SESSION["SES_USER_ID"] . " OR friendship.sender_id !=" . $_SESSION["SES_USER_ID"] . ")                  
  AND user.id != " . $_SESSION["SES_USER_ID"] . "");
  $new_friends2->setFetchMode(PDO::FETCH_ASSOC);
  $new_friends_data2 = $new_friends->fetchAll();
  //look carefully I change some equations from = to !=

WHERE (friendship.receiver_id !=" . $_SESSION["SES_USER_ID"] . " OR friendship.sender_id !=" . $_SESSION["SES_USER_ID"] . ")

我怎样才能修好它

基本上我想返回那些不是会话用户朋友的人

  $new_friends2 = $db->query("
  SELECT user.id, user.name_surname
  FROM user
  JOIN friendship ON user.id = friendship.sender_id or user.id = friendship.receiver_id
  WHERE (friendship.receiver_id !=" . $_SESSION["SES_USER_ID"] . " OR friendship.sender_id !=" . $_SESSION["SES_USER_ID"] . ")                  
  AND user.id != " . $_SESSION["SES_USER_ID"] . "");
  $new_friends2->setFetchMode(PDO::FETCH_ASSOC);
  $new_friends_data2 = $new_friends->fetchAll();
  //look carefully I change some equations from = to !=

WHERE (friendship.receiver_id !=" . $_SESSION["SES_USER_ID"] . " OR friendship.sender_id !=" . $_SESSION["SES_USER_ID"] . ")

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或者在这里允许其中一列将SES_USER_ID更改为，并且

您的问题不够清楚

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但是看看这个问题，你应该用

和
替换
或
 @Mihaiıthink在我的代码中ses id并不重要，因为基本上我想返回那些不是会话用户朋友的人。你应该在第二部分的WHERE子句中使用，而不是OR。我将“或”改为“到”和“仍然返回朋友。你能发布一些示例数据吗？1和2查询之间的区别是什么？