Php 如何制作表格并保存url和html代码？
考虑下面给出的PHP代码。此代码用于在输入网站url时获取html源代码。现在我的问题是，我想创建一个数据库，并将url和html代码保存在该表中。在下面的代码中，变量$WEBITE和$query包含url和html代码。那我该怎么做呢Php 如何制作表格并保存url和html代码？,php,html,mysql,sql,database,Php,Html,Mysql,Sql,Database,考虑下面给出的PHP代码。此代码用于在输入网站url时获取html源代码。现在我的问题是，我想创建一个数据库，并将url和html代码保存在该表中。在下面的代码中，变量$WEBITE和$query包含url和html代码。那我该怎么做呢 <!DOCTYPE HTML> <html> <head> <style> .error {color: #FF0000;} </style> </head> <bo
<!DOCTYPE HTML>
<html>
<head>
<style>
.error {color: #FF0000;}
</style>
</head>
<body>
<?php
$websiteErr = "";
$website = "";
if ($_SERVER["REQUEST_METHOD"] == "POST") {
if (empty($_POST["website"])) {
$website = "";
} else {
$website = test_input($_POST["website"]);
// check if URL address syntax is valid (this regular expression also allows dashes in the URL)
if (!preg_match("/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&@#\/%?=~_|!:,.;]*[-a-z0-9+&@#\/%=~_|]/i",$website)) {
$websiteErr = "Invalid URL";
}
}
}
function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
?>
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
Website: <input type="text" name="website">
<?php echo $websiteErr;?>
<br><br>
<input type="submit" name="submit" value="Submit">
</form>
<?php
$curl_handle=curl_init();
curl_setopt($curl_handle, CURLOPT_URL,$website);
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl_handle, CURLOPT_USERAGENT, 'Mozilla/5.0');
$query = curl_exec($curl_handle);
curl_close($curl_handle);
$query = htmlentities($query);
echo $query;
?>
</body>
</html>
您可以使用以下函数获取当前页面的url
function getUrl() {
$url = @( $_SERVER["HTTPS"] != 'on' ) ? 'http://'.$_SERVER["SERVER_NAME"] : 'https://'.$_SERVER["SERVER_NAME"];
$url .= ( $_SERVER["SERVER_PORT"] !== 80 ) ? ":".$_SERVER["SERVER_PORT"] : "";
$url .= $_SERVER["REQUEST_URI"];
return $url;
}
$current_url = getUrl();
$page_content = file_get_contents($current_url); // to get content of the page
//Or You can
ob_start();
$page_content = ob_get_content();