Php 合并每行中具有相同产品标识但不同样式标识的行

我在实现我想要的输出时遇到问题。我有一个包含产品id和样式id的表。每个产品包含1个或多个不同的样式。style_id列不能与任何行的组合相同

注意我想通过SQL查询或使用PHP代码来实现这个结果

产品风格

id      product_id     style_id
1           1             1
2           1             2
3           1             3
4           1             4
5           2             1

我想通过SQL查询或使用PHP代码来实现这个结果

  Array[12][
    {
      "id": 1,
      "name": "Product sample",
      "description": "Sample",
      "price": "11.00",
      "level": "school",
      "style_name":{[
           "Style 1",
           "Style 2",
           "Style 3",
           "Style 4"
          ]
      }
      "style_id": {[
          1,
          2,
          3,
          4,
        ]
      },
      "rank_id": 232
    }
    {
      "id": 2,
      "name": "Sample 2",
      "description": "Sample 2",
      "price": "10.00",
      "level": "school",
      "style_name": "Karate",
      "style_id": 1,
      "rank_id": 232
    }
  ]

这是我的当前代码。

$grading_products= \DB::table('products as p')
                  ->leftjoin('product_style as ps', 'p.id', '=', 'ps.product_id')
                  ->join('style_users as su', 'ps.style_id', '=', 'su.style_id')
                  ->join('styles as s', 'ps.style_id', '=', 's.id')
                  ->whereRaw('su.user_id = ' .$id. ' AND p.product_type_id = 1 AND p.service_sub_type_id = 2')
                  ->select('p.id', 'p.name', 'p.description', 'p.price', 'p.level', 'ps.product_id', 's.name as style_name', 'ps.style_id as ps_style', 'su.style_id', 'su.rank_id')
                  ->get();

这是我当前的输出

Array[12][
  {
    "id": 1,
    "name": "Product Sample",
    "description": "Sample",
    "price": "11.00",
    "level": "school",
    "style_name": "style 1",
    "style_id": 1,
    "rank_id": 232
  },
  {
    "id": 1,
    "name": "Product Sample",
    "description": "Sample",
    "price": "11.00",
    "level": "school",
    "style_name": "style 2",
    "style_id": 2,
    "rank_id": 232
  }
  {
      "id": 2,
      "name": "Sample 2",
      "description": "Sample 2",
      "price": "10.00",
      "level": "school",
      "style_name": "Karate",
      "style_id": 1,
      "rank_id": 232
  },
]

---

注意我想通过SQL查询或使用PHP代码来实现这个结果。

以当前输出为起点，这里有一个混乱的解决方案：

$new_output = [];

$keyed = [];

foreach ($current_output as $row) {
    $keyed[$row['id']]['style_name'][] = $row['style_name'];

    $keyed[$row['id']]['style_id'][] = $row['style_id'];

    $keyed[$row['id']]['row'] = $row;
}

foreach ($keyed as $id => $data) {
    $row = $data['row'];

    $temp_output = [
        'id' => $id,
        'name' => $row['name'],
        'description' => $row['description'],
        'price' => $row['price'],
        'level' => $row['level'],
    ];

    if (count($keyed[$row['id']]['style_name']) > 1) {
        $temp_output['style_name'] = $data['style_name'];
    } else {
        $temp_output['style_name'] = $data['style_name'][0];
    }

    if (count($keyed[$row['id']]['style_id']) > 1) {
        $temp_output['style_id'] = $data['style_id'];
    } else {
        $temp_output['style_id'] = $data['style_id'][0];
    }

    $temp_output['rank_id'] = $row['rank_id'];

    $new_output[] = $temp_output;
}

---

（未测试）

数据库将为每个唯一组合提供一个新行。您必须遍历脚本中的结果才能创建要查找的数组。是的，它将为每个唯一的组合创建一个新行。这就是我寻求帮助的原因，我如何才能实现我想要的预期输出。看看GROUP_CONCAT：