Php 如何在android中将json响应值存储到edittext中
您好,在这个getting reg_中没有来自数据库的数组值,我希望在不单击任何按钮的情况下将该值显示到Php 如何在android中将json响应值存储到edittext中,php,android,json,Php,Android,Json,您好,在这个getting reg_中没有来自数据库的数组值,我希望在不单击任何按钮的情况下将该值显示到EditText 有谁能帮我显示EditText值 类文件 String RegNo = DatabaseUtility.executeQueryPhp("reg",""); System.out.print(RegNo); try { JSONArray JA = new JSONArray(RegNo);
EditText
有谁能帮我显示EditText
值类文件
String RegNo = DatabaseUtility.executeQueryPhp("reg","");
System.out.print(RegNo);
try
{
JSONArray JA = new JSONArray(RegNo);
reg_no = new String[JA.length()];
for(int i=0;i<JA.length();i++)
{
reg_no[i] = JA.getJSONObject(i).getString("reg_no");
}
}
catch(Exception e)
{
Log.e("Fail 3", e.toString());
}
String RegNo=DatabaseUtility.executeQueryPhp(“reg”,”);
系统输出打印(注册号);
尝试
{
JSONArray JA=新JSONArray(RegNo);
reg_no=新字符串[JA.length()];
对于(int i=0;i只需执行以下操作:
String value = "";
for(int i=0;i<JA.length();i++)
{
reg_no[i] = JA.getJSONObject(i).getString("reg_no");
value+=reg_no[i];
}
myEditText.setText(value);
字符串值=”;
用于(int i=0;i用于在新的EditText
for(int i=0;i<JA.length();i++)
{
reg_no[i] = JA.getJSONObject(i).getString("reg_no");
EditText edit = new EditText(getApplicationContext());
edit.setText(reg_no[i]);
}
试试这个
for (int i = 0; i < JA.length(); i++)
{
JSONObject jsonObject = JA.getJSONObject(i);
reg_no[i] = jsonObject.getInt("reg_no");
editText[i].setText(reg_no[i].toString);
}
for(int i=0;i
您也可以使用StringBuilder
类
StringBuilder sb = new StringBuilder();
String RegNo = DatabaseUtility.executeQueryPhp("reg","");
System.out.print(RegNo);
try
{
JSONArray JA = new JSONArray(RegNo);
reg_no = new String[JA.length()];
for(int i=0;i<JA.length();i++)
{
reg_no[i] = JA.getJSONObject(i).getString("reg_no");
sb.append(reg_no[i]);
}
myEditText.setText(sb.toString());
}
catch(Exception e)
{
Log.e("Fail 3", e.toString());
}
StringBuilder sb=新建StringBuilder();
String RegNo=DatabaseUtility.executeQueryPhp(“reg”,”);
系统输出打印(注册号);
尝试
{
JSONArray JA=新JSONArray(RegNo);
reg_no=新字符串[JA.length()];
for(int i=0;i如何将PAT追加到reg_now中,什么是PAT?m不是getting@W-I-Z-A-R-D+1谢谢你帮我上去。谢谢:)@W-I-Z-A-R-D谢谢:)
StringBuilder sb = new StringBuilder();
String RegNo = DatabaseUtility.executeQueryPhp("reg","");
System.out.print(RegNo);
try
{
JSONArray JA = new JSONArray(RegNo);
reg_no = new String[JA.length()];
for(int i=0;i<JA.length();i++)
{
reg_no[i] = JA.getJSONObject(i).getString("reg_no");
sb.append(reg_no[i]);
}
myEditText.setText(sb.toString());
}
catch(Exception e)
{
Log.e("Fail 3", e.toString());
}