Php 不按ID的拉维关系'；s

我有两张这样的桌子：

作者表 -身份证 -书号 -名字

书桌 -身份证 -参考号 -作者 -头衔

books表上的ref与authors表上的book_id相同，但在我看来，这样做似乎无法获取authors书籍：

{{$author->books->first（）->>title}

我的作者和书籍模型如下所示：

class Authors extends \Eloquent {

protected $guarded = ['id'];

public $table = 'authors';

public $timestamps = false;

public function books()
{
    return $this->hasMany('Books', "author","name");
}

 }


 class Books extends \Eloquent {

protected $guarded = ['id'];

public $timestamps = false;

public function author()
{
    return $this->hasOne('Authors');
}

public function categories(){
    return $this->hasMany('Categories');
}

}

---

真的需要一些帮助

您可以在

hasMany

中传递外键和本地键，但看起来您将

author

作为外键传递，

name

作为本地键传递。外键应为

ref

，本地键应为

book\u id

class Authors extends \Eloquent {

    protected $guarded = ['id'];

    public $table = 'authors';

    public $timestamps = false;

    public function books()
    {
        return $this->hasMany('Books', "ref", "book_id");
    }

}


class Books extends \Eloquent {

    protected $guarded = ['id'];

    public $timestamps = false;

    public function author()
    {
        return $this->hasOne('Authors');
    }

    public function categories(){
        return $this->hasMany('Categories');
    }

}

---

谢谢，我想我把自己的领域弄得一团糟，非常感激。