如何从查看页面中的站点url获取ID http://localhost/cisbeadmin/index.php/conuser/edituser/.$row->$id\U pegawai

如何从CodeIgniter中的站点url获取id？ 这是我在“查看”页面中的代码：

http://localhost/cisbeadmin/index.php/conuser/edituser/.$row->$id_pegawai

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首先，您不需要直接进入视图。您应该在控制器的方法中获得它。在您的情况下，方法名称是edituser

以下是一种从url获取id的方法：

<a href="<?php echo site_url('conuser/edituser/.$row->$id_pegawai'); ?>  "> <i class="fa fa-edit"></i></a>

希望我能详细解释。如果你对此有任何异议，请告诉我

用这个替换代码

// Make sure your segment possition is correct and place few lines of code in starting of your method edituser()
$id = $this->uri->segment(3)) != '' && is_numeric($this->uri->segment(3)) && $this->uri->segment(3) > 0 ? $this->uri->segment(3) : false;

// After getting $id check if it is false or having value in it
if($id == false){
// If URL does not having id then it should show 404 error which is done by below line
   show_404();
}

// Pass $id value for view file same as we pass other values.

<a href="<?php echo site_url('conuser/edituser/'.$row->$id_pegawai); ?>  "> <i class="fa fa-edit"></i></a>

$id_pegawai = $this->uri->segment(2);