这个PHP_MYSQL更新commad中有什么错误?
更新命令中有什么错误??它不会更新数据库吗?这个PHP_MYSQL更新commad中有什么错误?,php,mysql,Php,Mysql,更新命令中有什么错误??它不会更新数据库吗? if($action=="new") { $query1="insert into activity_basic_info(activity_id) values($activity_id)"; $result1=mysql_query($query1); if($result1) echo "01"; else echo "00"; } else { $query="updat
if($action=="new")
{
$query1="insert into activity_basic_info(activity_id) values($activity_id)";
$result1=mysql_query($query1);
if($result1)
echo "01";
else
echo "00";
}
else
{
$query="update activity_basic_info set";
if(isset($name))
$query = $query." name='$name',";
if($describtion!="" && describtion!=NULL)
$query = $query." describtion='$describtion',";
if($city!=NULL&&$city!="")
$query = $query." city_id=$city,";
if($region!=NULL)
$query = $query." region_id=$region,";
if($street!=NULL)
$query = $query." street_id=$street,";
if($telephone!="")
$query = $query." telephone=$telephone,";
if($email!=NULL&&$email!="")
$query = $query." email='$email',";
if($url!=NULL&&$url!="")
$query = $query." url='$url'";
else
$query = $query."url=''";
$query = $query." where activity_id=$activity_id";
$result=mysql_query($query);
echo $query;
}
?>
您应该检查$result=mysql\u query($query)是否成功;如果为false,则检查mysql\u error()的值。查询后mysql\u error()的输出是什么?OMG OMG OMF。。没有选择数据库!!!!谢谢亲爱的。。这是一个非常愚蠢的错误,在这段代码中有很多失败的可能性。请发布错误消息请注意,
else
code$query=$query.“url=''”中没有前导空格代码>。它可以进行如下查询:updateactivity\u basic\u info seturl=''