动态url mysql php如何
我正在wordpress网站上构建一个表,显示从一个表中排序的数据 我不能正确地将标题更改为URL,这是来自同一数据库的可变slug 基本url保持不变,只是slug发生了变化 然后是鼻涕虫 这是到目前为止我的代码动态url mysql php如何,php,mysql,url,dynamic,Php,Mysql,Url,Dynamic,我正在wordpress网站上构建一个表,显示从一个表中排序的数据 我不能正确地将标题更改为URL,这是来自同一数据库的可变slug 基本url保持不变,只是slug发生了变化 然后是鼻涕虫 这是到目前为止我的代码 function dbTEST($atts, $content = null) { // Get all the data from the "job board" table $result = mysql_query("SELECT * FROM wpjb_job WHERE
function dbTEST($atts, $content = null) {
// Get all the data from the "job board" table
$result = mysql_query("SELECT * FROM wpjb_job WHERE job_country='72' ORDER BY job_title")
or die(mysql_error());
echo "<table border='1'>";
echo "<tr> <th>Job</th> <th>Company</th> </tr>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result )) {
// Print out the contents of each row into a table
echo "<tr><td>";
#---------- I need this job_title to url link to the job_slug
echo $row['job_title'];
echo $row['job_slug'];
echo "</td><td>";
echo $row['company_name'];
echo "</td></tr>";
}
echo "</table>";
}
试试这个:
echo "<a href=wwww.thesite.com/job/view/".$row['job_slug'].">".$row['job_title']."</a>"
谢谢,这就是我最后要做的,除了我有echo'