复杂PHP数组中的搜索值

我已经读过很多关于从复杂数组中寻找值的文章，但所有这些都只能达到第二级。有人能给我提供递归查找地址行2中的值（例如state）的代码吗

我有下面的JSON

{
  "company": {
    "id": "123456",
    "name": "Test Company LLC.",
    "FEIN": "22-2222222",
    "address": {
      "address_line_1": {
        "street": "1 Street St, Suite 12",
        "city": "San Francisco",
        "postalCode": "123456"
      },
      "address_line_2": {
        "state": "CA",
        "country": "USA"
      }
    },
    "phone": "1-800-XXX-XXXX",
    "fax": "1-800-XXX-XXXX",
    "email": "admin@abc.com",
    "URL": "www.abc.com"
  },
  "producer": {
    "id": "LLXXXX",
    "name": "Test Name",
    "phone": "555-555-5555",
    "mobile": "555-555-5555",
    "fax": "555-555-5555",
    "email": "test@abc.com",
    "producerSubCode": "111",
    "NIPRId": "123456",
    "stateProducerId": "12344"
  }
}

~Harshit

您可以使用它来获取给定密钥的值

$array=json_decode（$json，true）

---

$names=array_列（$array，'name'）

而不是将其设置为数组。用正则表达式将其解析为字符串怎么样

$find = "San Francisco";
$re = '/(' . $find . ')\":\s\"(.*?)\"|\"(\w+)\":\s\"(' . $find . ')/m';
$str = '{ "company": { "id": "123456", "name": "Test Company LLC.", "FEIN": "22-2222222", "address": { "address_line_1": { "street": "1 Street St, Suite 12", "city": "San Francisco", "postalCode": "123456" }, "address_line_2": { "state": "CA", "country": "USA" } }, "phone": "1-800-XXX-XXXX", "fax": "1-800-XXX-XXXX", "email": "admin@abc.com", "URL": "www.abc.com" }, "producer": { "id": "LLXXXX", "name": "Test Name", "phone": "555-555-5555", "mobile": "555-555-5555", "fax": "555-555-5555", "email": "test@abc.com", "producerSubCode": "111", "NIPRId": "123456", "stateProducerId": "12344" } }';

preg_match_all($re, $str, $matches);

$result["key-match"] = array_slice(array_column($matches, 0),1,2);
$result["value-match"] = array_slice(array_column($matches, 0),3,2);
var_dump($result);

$find

可以是键或值。
如果是键匹配或值匹配，结果数组将包含两个子数组

假设

数组中的每个键和值都是唯一的

功能定义

函数

getData（）

在数组中搜索给定的字符串

• 如果字符串恰好是一个

  键

  ，它将返回一个布尔值

  true

• 如果字符串恰好是数组中的

  值

  ，它将返回一个

  键

• 如果字符串既不是

  键

  也不是

  值

  ，它将返回布尔值

  false

---

您能编辑您的问题并提及示例输入和输出以及您尝试了什么吗？@vivek_23示例输入可以是数组中的任何键或值，如果我理解正确的话。所以只选一个。@Andreas所以，示例输入恰好是一个

键

，而不是

值

，我按原样返回？我想您应该同时输出键和值。但我不确定。有没有可能的复制品，我们可以得到我们要去的vlue的绝对地址。i、 e.在“城市”处，输出为“公司=>地址=>地址\线路\ 1=>城市”？是的，有。您希望

“company=>address=>address\u line\u 1=>city”

成为字符串还是任何其他形式的字符串？成为一个字符串OnlyTanks@vivek\u 23，这很有帮助。你让我开心。

<?php

$json_string = '{"company":{"id":"123456","name":"Test Company LLC.","FEIN":"22-2222222","address":{"address_line_1":{"street":"1 Street St, Suite 12","city":"San Francisco","postalCode":"123456"},"address_line_2":{"state":"CA","country":"USA"}},"phone":"1-800-XXX-XXXX","fax":"1-800-XXX-XXXX","email":"admin@abc.com","URL":"www.abc.com"},"producer":{"id":"LLXXXX","name":"Test Name","phone":"555-555-5555","mobile":"555-555-5555","fax":"555-555-5555","email":"test@abc.com","producerSubCode":"111","NIPRId":"123456","stateProducerId":"12344"}}';

$json_array = json_decode($json_string,true);

function getData($json_array,$search_value){
    foreach($json_array as $each_key => $each_value){
        if($each_key === $search_value) return true;
        if(is_array($each_value)){
            $return_value = getData($each_value,$search_value);
            if($return_value !== false) return $return_value === true ? $return_value : $each_key."=>".$return_value;
        }else if($each_value === $search_value){
            return $each_key;
        }
    }

    return false;
}

echo "<pre>";
var_dump(getData($json_array,'San Francisco'));
var_dump(getData($json_array,'producerSubCode'));
var_dump(getData($json_array,'abc123'));

string(38) "company=>address=>address_line_1=>city"
bool(true)
bool(false)