Php 基于id合并数组数据

原始数据

Array
  (
    [0] => Array
      (
        [bet_id] => 7
        [agent_id] => 2
        [bet_type] => 1
        [amount] => 0
        [name] => ethan
       )

     [1] => Array
          (
            [bet_id] => 7
            [agent_id] => 2
            [bet_type] => 3
            [amount] => 0
            [name] => ethan
           )

      [2] => Array
             (
               [bet_id] => 7
               [agent_id] => 4
               [bet_type] => 1
               [amount] => 2
               [name] => alex
              )

       [3] => Array
               (
                 [bet_id] => 7
                 [agent_id] => 4
                 [bet_type] => 4
                 [amount] => 100
                 [name] => alex
               ) 
    )

我陷入了将上述数据分离的逻辑思维。上面的数组将循环所有用户数据，这里有2个用户。如何基于agentId将其合并为2个数组。它将变成如下所示

Array
     ( 
      [0] => Array 
         (
            [agent_id] => 2
            [name] => ethan
            [1] => 2    //bettype & amount
            [3] => 0    //bettype & amount
            [bet_id] => 7                       
          )                                           
     [1] => Array 
          (
             [agent_id] => 4
             [name] => alex
             [1] => 0     //bettype & amount
             [4] => 100    //bettype & amount
             [bet_id] => 7                       
          )
     )

---

注意：唯一不同的数据是代理id、下注类型和金额。其他数据将是相同的。

将

bet\u type

作为键，将

amount

作为值，会使数据结构看起来很糟糕，但让我们来创建它

$result = [];
foreach($data as $user) {
    $found = -1;
    for($i = 0; $i<count($result); $i++) {
        if($result[$i]["agent_id"] == $user["agent_id"]) {
            $found = $i;
            break;
        }
    }
    // if not found, create new
    if($found == -1) {
        $result[] = [
            "agent_id" => $user["agent_id"],
            "name" => $user["name"],
            "bet_id" => $user["bet_id"],
            $user["bet_type"] => $user["amount"]
        ];
    } else {
        $result[$i][$user["bet_type"]] = $user["amount"];
    }
}

我建议你改变

bet\u type

的位置，把它们放在子数组中，如下所示

Array
(
    [0] => Array
        (
            [agent_id] => 2
            [name] => ethan
            [bet_id] => 7
            [1] => 0
            [3] => 0
        )

    [1] => Array
        (
            [agent_id] => 4
            [name] => alex
            [bet_id] => 7
            [1] => 2
            [4] => 100
        )

)

$result = [];
foreach($data as $user) {
    $found = -1;
    for($i = 0; $i<count($result); $i++) {
        if($result[$i]["agent_id"] == $user["agent_id"]) {
            $found = $i;
            break;
        }
    }
    // if not found, create new
    if($found == -1) {
        $result[] = [
            "agent_id" => $user["agent_id"],
            "name" => $user["name"],
            "bet_id" => $user["bet_id"],
            "details" => [
                $user["bet_type"] => $user["amount"]
            ]
        ];
    } else {
        $result[$i]["details"][$user["bet_type"]] = $user["amount"];
    }
}

(
    [0] => Array
        (
            [agent_id] => 2
            [name] => ethan
            [bet_id] => 7
            [details] => Array
                (
                    [1] => 0
                    [3] => 0
                )

        )

    [1] => Array
        (
            [agent_id] => 4
            [name] => alex
            [bet_id] => 7
            [details] => Array
                (
                    [1] => 2
                    [4] => 100
                )

        )

)

---

您是否尝试过使用常用的foreach？您确定使用下注类型作为键，使用金额作为值是一个好的解决方案吗？呃，仍然在考虑更好的方法，但遇到了以下问题：（.@MMMM欢迎来到Stack Overflow。请学习Stack Overflow的工作原理，并阅读如何提高问题的质量。然后，您的问题将包括您作为一个可由其他人编译和测试的源代码。请参阅：。向我们展示您尝试过的源代码，并解释它们是如何失败的。