Php 读入时是否可以操纵关联数组?
我为datatables引入了这个数组,并将其放入关联数组中。在使用datatables之前,我使用纯PHP创建我的表,并可以操作索引的arrray,下面是一个示例Php 读入时是否可以操纵关联数组?,php,jquery,arrays,datatable,jquery-datatables,Php,Jquery,Arrays,Datatable,Jquery Datatables,我为datatables引入了这个数组,并将其放入关联数组中。在使用datatables之前,我使用纯PHP创建我的表,并可以操作索引的arrray,下面是一个示例 <?php foreach ($types as $val) { setlocale(LC_MONETARY, 'en_US'); echo '<tr>'; echo '<td>' . $val[0] . '</td>'; echo '<
<?php
foreach ($types as $val) {
setlocale(LC_MONETARY, 'en_US');
echo '<tr>';
echo '<td>' . $val[0] . '</td>';
echo '<td>' . $val[1] . '</td>';
echo '<td>' . $val[5] . '</td>';
echo '<td>' . number_format($val[2] * .01, 2) . '</td>';
echo '<td>' . $val[3] . '</td >';
echo '<td>' . money_format('%2n', $val[4] * .01) . '</td>';
switch ($val[5]) {
case 'S';
echo '<td>' . money_format('%2n', $val[3]) . '</td>';
break;
case 'U';
echo '<td>U</td>';
break;
case 'H':
$totalHourly = ($val[2] * .01) * ($val[4] * .01);
echo '<td>' . $totalHourly . '</td>';
break;
case 'M':
echo '<td>M</td>';
break;
default;
if ($val[2] > 0) {
$totalGross = ($val[2] * .01) * ($val[4] * .01);
echo '<td>' . money_format('%.2n', $totalGross) . '</td>';
} else {
echo '<td>' . money_format('%.2n', $val[3]) . '</td>';
}
}
echo '<td><a href=EmployeeInfo.php?empNum=' . $val[0] . '>Info</a></td>';
echo '<td><a href=EmployeePayroll.php?empNum=' . $val[0] . '>Payroll</a></td>';
echo '</tr>';
}
?>
最后一行是我发现的操纵这个数组的最简单方法。是否有一种方法可以将相同的逻辑应用到关联数组,就像我应用索引数组一样?如果没有,添加逻辑然后创建关联数组的最佳方法是什么
这就是我所做的
while ($row = db2_fetch_array($stmt)) {
$empNum = $row[0];
$empName = $row[1];
$unitRate = $row[2];
$salary = $row[3];
$hourly = $row[4];
$appFlag = $row[5];
$app1 = $row[6];
$app2 = $row[7];
$app3 = $row[8];
$app4 = $row[9];
$app5 = $row[10];
$uni1 = $row[11];
$uni2 = $row[12];
$uni3 = $row[13];
$uni4 = $row[14];
$uni5 = $row[15];
switch ($row[5]) {
case 'S';
$gross = $row[3];
break;
default;
if ($row[2] > 0) {
$gross = ($row[2] * .01) * ($row[4] * .01);
} else {
$gross = $row[3];
}
}
$load['data'][] = array(
'empNum' => $empNum,
'empName' => $empName,
'unitRate' => $unitRate,
'salary' => $salary,
'hourly' => $hourly,
'appFlag' => $appFlag,
'app1' => $app1,
'app2' => $app2,
'app3' => $app3,
'app4' => $app4,
'app5' => $app5,
'uni1' => $uni1,
'uni2' => $uni2,
'uni3' => $uni3,
'uni4' => $uni4,
'uni5' => $uni5,
'gross' => $gross
);
没有理由一蹴而就。您可以创建子数组,根据需要对其进行操作,然后将其填充到父数组中
$foo = array()
$foo['empnum'] = ...
...
$foo['gross'] = $foo['x'] * $foo['y'];
if ( ...) {
$foo['if_results'] = ... :
}
$data[] = $foo;
请注意,您不能将if/switch嵌入…=大堆释义如果/switch不是函数调用,则它们没有返回值,因此可以在预期为函数调用的上下文中使用。您可以使用构造遍历关联数组并操作其内容:
$data = array(
'empNum' => $row[0],
'empName' => $row[1],
'unitRate' => $row[2],
'salary' => $row[3],
'hourly' => $row[4],
'appFlag' => $row[5],
'app1' => $row[6],
'app2' => $row[7],
'app3' => $row[8],
'app4' => $row[9],
'app5' => $row[10],
'uni1' => $row[11],
'uni2' => $row[12],
'uni3' => $row[13],
'uni4' => $row[14],
'uni5' => $row[15],
'gross' => ($row[2] * .01) * ($row[4] * .01)
);
foreach($data as $key => $value) {
$data[$key] = 1; // add your complicated logic here
}
$load['data'][] = $data;
如果我很了解你,你会认为你需要直接在阵列防御中执行ifs和whiles。但事实并非如此。您可以这样做:
$count = 0;
while ($row = db2_fetch_array($stmt)) {
$load['data'][] = array(
'empNum' => $row[0],
'empName' => $row[1],
'unitRate' => $row[2],
'salary' => $row[3],
'hourly' => $row[4],
'appFlag' => $row[5],
'app1' => $row[6],
'app2' => $row[7],
'app3' => $row[8],
'app4' => $row[9],
'app5' => $row[10],
'uni1' => $row[11],
'uni2' => $row[12],
'uni3' => $row[13],
'uni4' => $row[14],
'uni5' => $row[15],
'gross' => ($row[2] * .01) * ($row[4] * .01)
);
if <condition> {
$load['data'][$count]['uni3'] = <whatever>;
$load['data'][$count]['gross'] = <whatever>;
} else {
$load['data'][$count]['uni5'] = <whatever>;
$load['data'][$count]['gross'] = <whatever2>;
}
<any other code you what>
$count++;
}
你现在做的很好。它不起作用吗?还可以在DataTables的列呈现回调中操作数据。最后一行工作正常,但我需要执行更复杂的逻辑。使用switch和if语句。那么是什么阻止您将这些switch和if语句放在while循环中呢?我试着这么做。我复制并粘贴了第一个示例中的switch语句,并将$row[]替换为关联的等效语句。它不起作用,或者我做得不正确。一旦我设置了if或switch,我就会得到一个错误。你需要显示你尝试过的代码,并扩展错误。这!!!!!我可以在数组中读取索引。我是否可以使用索引而不是关联名称,然后将其指定为关联数组?示例$foo=数组,如果$row[1]='something{$foo['result']}$foo['result']=$row['some_value_from_the_db']。或者你想在新数组中填充的任何东西。都不起作用。您将向父数组添加whatever,而不是新的empnum/empname/etc。。。大堆它必须是$load['data'][新数组的索引]['uni3']=。。。
$count = 0;
while ($row = db2_fetch_array($stmt)) {
$load['data'][] = array(
'empNum' => $row[0],
'empName' => $row[1],
'unitRate' => $row[2],
'salary' => $row[3],
'hourly' => $row[4],
'appFlag' => $row[5],
'app1' => $row[6],
'app2' => $row[7],
'app3' => $row[8],
'app4' => $row[9],
'app5' => $row[10],
'uni1' => $row[11],
'uni2' => $row[12],
'uni3' => $row[13],
'uni4' => $row[14],
'uni5' => $row[15],
'gross' => ($row[2] * .01) * ($row[4] * .01)
);
if <condition> {
$load['data'][$count]['uni3'] = <whatever>;
$load['data'][$count]['gross'] = <whatever>;
} else {
$load['data'][$count]['uni5'] = <whatever>;
$load['data'][$count]['gross'] = <whatever2>;
}
<any other code you what>
$count++;
}