Php 如何使用关联验证实体？

我有表格课：

...
public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder->add('name', TextType::class); 
    $builder->add('surname', TextType::class);
    $builder->add('address', IntegerType::class); // write custom field type?
}
...

我使用它来验证客户实体，其中$address字段是关联：

...
/**
 * @ORM\OneToOne(targetEntity="Address")
 * @Assert\CustomAddress // write this custom validation constraint?
 */
private $address;
...

现在如何验证$address值？现在我得到了（我并不惊讶的是）：

应为类型为“AppBundle\Entity\Address”的参数，并给定“string”

---

您需要为地址实体创建一个表单，例如：

use AppBundle\Entity\Address;
// ...

class AddressType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('address1', TextType::class); 
        $builder->add('city', TextType::class);
        // ...
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => Address::class,
        ]);
    }
}

use AppBundle\Form\Type\AddressType;

// ...

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder->add('name', TextType::class); 
    $builder->add('surname', TextType::class);
    $builder->add('address', AddressType::class);
}

然后更新您的

CustomerType

以使用该类，例如：

use AppBundle\Entity\Address;
// ...

class AddressType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('address1', TextType::class); 
        $builder->add('city', TextType::class);
        // ...
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => Address::class,
        ]);
    }
}

use AppBundle\Form\Type\AddressType;

// ...

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder->add('name', TextType::class); 
    $builder->add('surname', TextType::class);
    $builder->add('address', AddressType::class);
}

---

然后，您的地址实体将自动验证，而无需自定义验证约束。

Okey有效。所以现在我需要写转换器来从int转换到address实体？或者在$fomr->submit（…）之前获取它？我是对的？你不应该做这样的事情-你的关联被视为一个完整的实体，而不是传统的外键整数。所以你根本不需要数据转换器。谢谢你的回答。你是对的。不管怎样，我最终得到了一个例外：“复合表单在提交时需要一个数组或NULL”。我现在放弃了，我明天会尝试解决这个问题。我从来没有见过这样的错误：）如果你需要更多的帮助，请告诉我