Php 我想使用codeigniter对每个帖子发表所有评论

图中显示了我希望显示每个帖子所有评论的所有帖子。我用红色标记了评论部分`

public function forum(){
    $config['base_url'] = site_url('tourism_con/forum');  
    $config['total_rows'] = $this->db->get('forum_posts')->num_rows();
    $config['uri_segment'] = 3;
    $config['per_page'] = 5; 
    $config['full_tag_open'] = "<ul class='pagination pagination-lg'>";
    $config['full_tag_close'] ="</ul>";
    $config['num_tag_open'] = "<li>";
    $config['num_tag_close'] = '</li>';
    $config['cur_tag_open'] = "<li class='disabled'><li class='active'><a href='#'>";
    $config['cur_tag_close'] = "<span class='sr-only'></span></a></li>";
    $config['next_tag_open'] = "<li>";
    $config['next_tagl_close'] = "</li>";
    $config['prev_tag_open'] = "<li>";
    $config['prev_tagl_close'] = "</li>";
    $config['first_tag_open'] = "<li>";
    $config['first_tagl_close'] = "</li>";
    $config['last_tag_open'] = "<li>";
    $config['last_tagl_close'] = "</li>";
    $data['forum_title']='Forum :: Home Page';
    $data['forumPosts']='forumPosts';
    $data['forum_details']=  $this->tourism_model->get_forum_post($config);
    $data['comment_count']=$this->tourism_model->get_comments_by_post();
    $this->load->view('Forum/forum_home',$data);
}

下面是模型中注释的代码，用于从数据库检索注释

public function get_comments_by_post(){
   $this->db->select('comment_id');
   $this->db->distinct();
   $this->db->from('comment');
   $query = $this->db->get();
   return $query->num_rows();
}

查看代码部分

作者：

发布于

在

get\u comments\u by\u post

功能中执行此操作：过去

post\u id

public function get_comments_by_post($postid){
    $q = $this->db->query("SELECT * FROM comments WHERE post_id = $postid");
    if($q->num_rows() > 0) {
        return $q->result_array();
    } else {
        return '';
    }
}

---

然后使用

post\u id

作为标准选择您的评论，所有帖子一起从数据库中检索。我如何将post\u id从这些帖子中分离出来？如果不知道您的数据库结构post table和comment table，这个问题是无法回答的，因为它们是两个不同的表。因此，每当我需要数据时，我都会在这两个表上应用查询tables.it's not work.it show A PHP Error遇到严重性：错误消息：无法将stdClass类型的对象用作数组文件名：models/tourism\u model.PHP行号：144$all_posts[$i]['comment']=$this->get_comments\u by_post（$all_posts[$i]['post\u id'）$数据['forum\u details']=$this->tourism\u model->get\u forum\u post（$config）；在$data['forum\u details']中存储所有帖子信息。现在您只需告诉我如何将帖子id从数组中分离出来。然后我会将帖子id发送到model，它会发回每篇帖子的评论总数。@hmamun您可以发布

$data['forum\u details']

中的帖子吗，我将告诉您如何检索

post\u id

public function get_comments_by_post($postid){
    $q = $this->db->query("SELECT * FROM comments WHERE post_id = $postid");
    if($q->num_rows() > 0) {
        return $q->result_array();
    } else {
        return '';
    }
}