如何在PHP中查找数组值是否更改

我们有这样一个数组：

Array
(
    [0] => Array
        (
            [HASTANEADI] => MALATYA DEVLET HASTANESİ
            [SEHIR] => Malatya
            [DONEM] => NİSAN 2011
        )

    [1] => Array
        (
            [HASTANEADI] => MALATYA DEVLET HASTANESİ
            [SEHIR] => Malatya
            [DONEM] => MART 2011

        )

    [2] => Array
        (
            [HASTANEADI] => MALATYA DEVLET HASTANESİ
            [SEHIR] => Malatya
            [DONEM] => OCAK 2011

        )

    [3] => Array
        (
            [HASTANEADI] => DENİZLİ DEVLET HASTANESİ
            [SEHIR] => Denizli
            [DONEM] => NİSAN 2011

        )

    [4] => Array
        (
            [HASTANEADI] => DENİZLİ DEVLET HASTANESİ
            [SEHIR] => Denizli
            [DONEM] => MART 2011

        )

    [5] => Array
        (
            [HASTANEADI] => DENİZLİ DEVLET HASTANESİ
            [SEHIR] => Denizli
            [DONEM] => OCAK 2011

        )

 'NİSAN 2011','MART 2011','OCAK 2011',

我想为HASTANE写一次DONEM。我想写DONEM值，而不是每个HASTANE。因为DONEM对每个HASTANE都是一样的

所以我尝试了以下代码：

$categories="";
foreach ($hastane as $h) {

     $categories.="'$h['DONEM']',";


    }

 echo $categories;



'NİSAN 2011','MART 2011','OCAK 2011','NİSAN 2011','MART 2011','OCAK 2011',

但我想这样输出：

Array
(
    [0] => Array
        (
            [HASTANEADI] => MALATYA DEVLET HASTANESİ
            [SEHIR] => Malatya
            [DONEM] => NİSAN 2011
        )

    [1] => Array
        (
            [HASTANEADI] => MALATYA DEVLET HASTANESİ
            [SEHIR] => Malatya
            [DONEM] => MART 2011

        )

    [2] => Array
        (
            [HASTANEADI] => MALATYA DEVLET HASTANESİ
            [SEHIR] => Malatya
            [DONEM] => OCAK 2011

        )

    [3] => Array
        (
            [HASTANEADI] => DENİZLİ DEVLET HASTANESİ
            [SEHIR] => Denizli
            [DONEM] => NİSAN 2011

        )

    [4] => Array
        (
            [HASTANEADI] => DENİZLİ DEVLET HASTANESİ
            [SEHIR] => Denizli
            [DONEM] => MART 2011

        )

    [5] => Array
        (
            [HASTANEADI] => DENİZLİ DEVLET HASTANESİ
            [SEHIR] => Denizli
            [DONEM] => OCAK 2011

        )

 'NİSAN 2011','MART 2011','OCAK 2011',

我不想把这些价值观搞混。 那我该怎么做呢

---

谢谢

一个选项是：

$unique = array();
foreach ($hastane as $h) {
  $unique[$h['DONEM']] = 1;
}

$categories="";
foreach(array_keys($unique) as $donem){
  $categories.= "'{$donem}',";
}

---

就像上面的注释一样，一种方法是使用

array\u unique（）

。收集所需数组中的所有值，然后应用函数。要显示它们，只需使用

内爆（）

：

如果您已经在使用PHP5.5或更高版本，还可以使用

array\u column

$DONEM = array_unique(array_column($array, 'DONEM'));
echo implode(', ', $DONEM);

---

正如@zerkms所说的，你可以试试array_unique->@MarcoMura，正如你所说的，正如我所说的，Indeedang，甚至没有想到array_unique。想得太多了：/@zerkms哈哈，你让我的日子过得很开心