Php 如何在MYSQL中使用REGEXP来匹配数组中的日期?
我试图在很多年中匹配表的发布日期起的年份。我使用的是laravel(PHP) 我写过这样的东西:Php 如何在MYSQL中使用REGEXP来匹配数组中的日期?,php,mysql,regex,laravel,Php,Mysql,Regex,Laravel,我试图在很多年中匹配表的发布日期起的年份。我使用的是laravel(PHP) 我写过这样的东西: if($this->request->has('publication_years')){ $years = implode('-[0-9]{2}-[0-9]{2}|', explode(',', $this->request->get('publication_years'))) . '-[0-9]{2}-[0-9]{2}'; $model = $mode
if($this->request->has('publication_years')){
$years = implode('-[0-9]{2}-[0-9]{2}|', explode(',', $this->request->get('publication_years'))) . '-[0-9]{2}-[0-9]{2}';
$model = $model->whereExists(function ($query) use ($years)
{
$query->select(DB::raw(1))
->from('patent')
->whereRaw('patent.id = document.documentable_id')
->whereRaw('document.documentable_type = "patent"')
->whereRaw('(patent.publication_date REGEXP (' . $years . '))');
});
}
这些年来就像出版年=20152016。我使用,
分隔符分解它们,然后对它们进行内爆,以使REGEXP模式与日期匹配。这之后几年的垃圾堆就像是2015-[0-9]{2}-[0-9]{2}2016-[0-9]{2}-[0-9]{2}
这在上个月起作用,但我仍然会出错,所以我猜MYSQL还有其他一些语法。我看到的错误是:
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[0-9]{2}-[0-9]{2}|2016-[0-9]{2}-[0-9]{2})))' at line 1 (SQL: select count(*) as aggregate from `document` where exists (select * from `folder` where `document`.`folder_id` = `folder`.`id` and (exists (select * from `user` inner join `accessible_by_user` on `user`.`id` = `accessible_by_user`.`user_id` where `accessible_by_user`.`accessible_id` = `folder`.`id` and `accessible_by_user`.`accessible_type` = folder and `user_id` = 1) or exists (select * from `role` inner join `accessible_by_role` on `role`.`id` = `accessible_by_role`.`role_id` where `accessible_by_role`.`accessible_id` = `folder`.`id` and `accessible_by_role`.`accessible_type` = folder and `role_id` in (1)))) and exists (select 1 from `patent` where patent.id = document.documentable_id and document.documentable_type = "patent" and (patent.publication_date REGEXP (2015-[0-9]{2}-[0-9]{2}|2016-[0-9]{2}-[0-9]{2}))))
我做错了什么?如何更正此问题?以下是准备在MySQL中使用正则表达式的方法:
$this_request_get_publication_years = "2015,2016,2017";
$years = '^(' . implode('|', explode(',',
$this_request_get_publication_years)) . ')-[0-9]{2}-[0-9]{2}';
echo "(patent.publication_date REGEXP '" . $years . "')";
// => (patent.publication_date REGEXP '^(2015|2016|2017)-[0-9]{2}-[0-9]{2}')
REGEXP'^(2015 | 2016 | 2017)-[0-9]{2}-[0-9]{2}'
将只获取以下记录:
-在字符串开头,让^
-三年中的任何一年(当然支持更多年)(2015年| 2016年| 2017年)
-后跟两位数字的连字符-[0-9]{2}
-同上-[0-9]{2}
后两个子模式可以收缩为
([0-9]{2}{2}
用单引号将正则表达式括起来,如REGEXP'(2015-[0-9]{2}..)
REGEXP'^(2016 | 2015)'Wow。就这样。我现在觉得自己很愚蠢。不管怎样,它成功了。谢谢你们。我认为我的正则表达式是错误的。所以,使用$years=“^(.str_replace(',','|',$this->request->get('publication_years'))。-[0-9]{2}-[0-9]{2}代码>和更改->whereRaw('(patent.publication_date REGEXP('.$years'))代码>至->whereRaw(“(patent.publication_date REGEXP\”.$years.”)代码>。对吗?